Full Syllabus-IV

Transcript

Full Syllabus-IV

Class XIII (Spartan Batch)
Full Syllabus-IV
1.
(f) transferring the recombinant DNA into the host
çÙ×A ·¤ÍÙæð ·¤æð ÂçÉ¸UØð ÌÍæ ÇUè°Ù° Âýæñlæðç»·¤è ·ð¤ çßçàæCU ¥Ùé·ý¤× ×ð´
âé×ðçÜÌ ·¤èçÁ°Ð
(a) DNA ·¤æ çßÜ»Ù
(b) ßæ´çàæ·¤ ÁèÙ ·¤æ ÂýßæüÙ
(c) DNA ·¤æ ¹´ÇUÙ
(d) ÂÚUÂæðáè ·¤æðçàæ·¤æ ·¤æ â´ßæüÙ
(e) DNA ¹´ÇU ·¤æ â´ßæãU·¤ âð Õ´æÙ
(f) ÂéÙØæðüÁè DNA ·¤æ ÂÚUÂæðáè ×ð´ SÍæÙæ´ÌÚUæ
(1) a, c, b, e, f & d
(2) a, b, c, e, f & d
(1) a, c, b, e, f & d
(2) a, b, c, e, f & d
(3) a, b, c, e, d & f
(4) c, a, b, e, f & d
(3) a, b, c, e, d & f
(4) c, a, b, e, f & d
Read the following statement and arrange them according 1.
to the process of RDT.
(a) isolation of DNA
(b) amplification of gene of interest
(c) fragmentation of DNA
(d) culturing the host cells
(e) ligation of DNA fragment into a vector.
2.
There are three basic steps in genetically modifying an 2.
Áèß ·ð¤ ¥æÙéßæ´çàæ·¤ M¤ÂæÌ´ÚUæ ×ð´ ×êÜÖêÌ ÌèÙ ¿ÚUæ ãUæðÌð ãñÚ
organism (ii) introduction of the identified plasmid into the host
(iii) maintenance of introduced DNA in the host and transfer
of the DNA to its progeny.
Read the above statements and choose the correct option(1) All are correct
(2) ii and iii are correct
(3) Only iii is correct
(4) None of these
3.
Which one is correctly matched in following options -
ßæ´çÀUÌ ÁèÙØéQ¤ ÜæÁç×ÇU ·¤è æãU¿æÙ
(ii) ç¿çãUÌ ÜæÁç×ÇU ·¤æ ÂÚUÂæðáè ×ð´ SÍæÙæÌ´ÚUæ
(iii) SÍæÙæÌ´çÚUÌ DNA ·¤æð ÂÚUÂæðáè ×ð´ âéÚUçÿæÌ ÚU¹Ùæ ÌÍæ ©Uâ·¤è â´ÌçÌ
×ð´ SÍæÙæÌ´çÚUÌ ·¤ÚUÙæÐ
çÎ° »° ·¤ÍÙæð´ ·¤æð ÂÉ¸U·¤ÚU âãUè çß·¤ËÂ ·¤æ ¿éÙæß ·¤èçÁ° (1) âÖè âãUè ãñU
(2) ii ÌÍæ iii âãUè ãñU
(3) ·ð¤ßÜ iii âãUè ãñU
(4) §UÙ×ð´ âð ·¤æð§üU ÙãUè´
çÙ×A ×ð´ âð ·¤æñÙâæ çß·¤ËÂ âãUè âé×ðçÜÌ ãñU (1) rop- DNA ÂýçÌ·ë¤çÌ ×ð´ Öæ» ÜðÙð ßæÜð ÂýæðÅUèÙ ·¤æ ·é¤ÅUÜð¹Ù ·¤ÚUÌæ
ãñUÐ
(2) EcoR1- GAATTC ¥Ùé·ý¤× ÂãU¿æÙÌæ ãñU
(3) âêÿ× ¥´ÌÑÿæðÂæ - Âæñææð´ ×ð´ ÁèÙ SÍæÙæ´ÌÚUæ ãðUÌé ©UÂØæð»è çßçæ ãñU
(i)
(i) identification of plasmid with desirable genes
3.
(1) rop- the proteins involved in the replication of the DNA.
(2) EcoR1- recognise GAATTC sequence.
(3) microinjection-suitable method of gene transfer for
plants.
(4) cryIAc & cryIAb-controls corn borer.
4.
Which of the group of crop plants, propagated by vegetative 4.
(4) cryIAc ÌÍæ cryIAb-×P¤æ ÀUðÎ·
·¤æð çÙØ´çæÌ ·¤ÚUÌæ ãñU
çÙ×AçÜç¹Ì ·¤æñÙâð ÂæÎÂæð´ ·ð¤ â×êãU ·¤æ ·¤æçØ·¤ ÂýßæüÙ ç·¤Øæ ÁæÌæ ãñU-
propagation ?
(1) ¥æÜê,
IV. It is responsible of eliminating certain genes.
ÂÂèÌæ, ·ð¤Üæ
(2) ØæÁ, æçÙØæ, Ùè´Õê
(3) ×ê´»È¤Üè, ·¤æÁê, ¥ÎÚU·¤
(4) »Ùæ, ¥ÎÚU·¤, ¥æÜê
UÁÙçÙ·¤ çß¿ÜÙ ·ð¤ çÜ° çÙ×A ×ð´ âð ·¤æñÙâæ ·¤ÍÙ âØ ãñU?
I. ØãU ãUæÇUèü-çßÙÕ»ü âæØ ·¤æð çß¿çÜÌ ·¤ÚUÌæ ãñ
II. ØãU ·ð¤ßÜ ÀUæðÅUè â×çCUØæð´ ×ð´ ãUæðÌæ ãñU
III. ØãU ·é¤ÀU ÁèÙæð´ ·ð¤ â´ÚUÿææ ·ð¤ çÜ° ©UæÚUÎæØè ãñU
IV. ØãU ·é¤ÀU ÁèÙæð´ ·ð¤ çÜ° çÙc·¤æâÙ ·ð¤ çÜ° ©UæÚUÎæØè ãñU
(1) I, II, III
(2) II, III, IV
(1) I, II, III
(2) II, III, IV
(3) I, II, IV
(4) I, II, III, IV
(3) I, II, IV
(4) I, II, III, IV
(1) Potato, Papaya, Banana
(2) Onion, Coriander, Lime
(3) Groundnut, Cashewnut, Ginger
(4) Sugarcane, Ginger, Potato
5.
Which of the following statements are true for genetic drift? 5.
I. It upsets the HardyWeinberg equilibrium
II. It operates only in small population
III. It is responsible for preserving certain genes
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DTS (Daily Test Series) for Re-AIPMT- 2015
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Full Syllabus-IV
6.
A diagram of T.S. of dicot root is given. Select the option 6.
which correctly labels A, B, C, D and E.
A
B
C
D
E
(1) Protoxylem Metaxylem
Phloem Pericycle
Endodermis
(1)
(2) Metaxylem
Phloem Pericycle
Endodermis
(2)
Protoxylem
(3) Protoxylem Metaxylem
Phloem Endodermis Pericycle
(3)
(4) Metaxylem
Phloem Endodermis Pericycle
(4)
7.
8.
9.
Protoxylem
Study carefully the following statements and select the 7.
incorrect one(s) (i) Lateral roots develops from pericycle
(ii) Endodermis is the innermost layer of cortex
(iii) Sap wood is the central, dark coloured, non-conducting
part of secondary xylem.
(1) (i) and (ii)
(2) (ii) and (iii)
(3) Only (i)
(4) Only (iii)
If we take a pBR322 and desired gene, both are cut by 8.
BamH1 enzyme. After that recombinant DNA is inserted
into host cell.
Choose the correct option according to above conclusion(1) recombinant plasmids will be lose amplicillin resistance
due to insertion of foreign DNA
(2) the transformatants are selected, growing on
tetracycline containing medium
(3) The recombinants will grow in ampicillin containing
medium but not on that containing tetracycline.
(4) Both (1) & (3) is correct
The sequence of events in geographic speciation is most 9.
likely to be :
(1) Genetic divergence ® geographic barrier ®
reproductive isolation
(2) Geographic barrier ® genetic divergence ® reproductive
isolation
(3) Reproductive isolation ® genetic divergence ®
geographic barrier
(4) Geographic barrier ® reproductive isolation ® genetic
çÎØæ »Øæ ç¿æ çmUÕèÁÂæè ×êÜ ·¤æ T.S. ãñUÐ
çÜ° âãUè çß·¤ËÂ ·¤æð ¿éçÙ°-
A, B, C, D
ÌÍæ
E
A
B
C
D
E
ÂýæðÅUæðÁæ§UÜ×
×ðÅUæÁæ§UÜ×
Üæð°×
Üæð°×
Üæð°×
Üæð°×
ÂçÚUÚÚÖ
ÂçÚUÚÚÖ
¥ÌÑà¿×ü
¥ÌÑà¿×ü
¥ÌÑà¿×ü
¥ÌÑà¿×ü
ÂçÚUÚÚÖ
ÂçÚUÚÚÖ
âÖè ·¤ÍÙæð´ ·¤æð ØæÙ âð ÂçÉUØð ÌÍæ ç·¤âè °·¤ »ÜÌ ·¤æ ¿ØÙ
·¤èçÁ°(i) Âæàßü ×êÜ ÂçÚUÚÚÖ âð ©UÂÙ ãUæðÌè ãñUÐ
(ii) °ÇUæðÇUç×üâ ßË·é¤ÅU ·¤è âÕâð ¥æÌçÚ·¤ ÂÚUÌ ãUæðÌè ãñUÐ
(iii) ÚUâ ·¤æDU, çmUÌèØ Áæ§UÜ× ·¤æ ·ð¤ÎýèØ, »ãUÚÔU ÚÚ» ·¤æ ¥â´¿çÚUÌ
Öæ» ãUæðÌæ ãñUÐ
(1) (i) ÌÍæ (ii)
(2) (ii) ÌÍæ (iii)
(3) ·ð¤ßÜ (i)
(4) ·ð¤ßÜ (iii)
°·¤ pBR322 ÌÍæ çßÁæçÌØ DNA ·¤æð BamH1 °´Áæ§U× âð cut ç·¤Øæ
§Uâ·ð¤ Âà¿æÌ÷ ÕÙð ÂéÙØæðü»Á DNA ·¤æð ÂÚUÂæðáè ·¤æðçàæ·¤æ ×ð´ SÍæÙæÌ´çÚUÌ
·¤ÚU ÎðÌð ãñUÐ
©UÂÚUæðQ¤ ÂýØæð» ·ð¤ ¥ÙéâæÚU âãUè çß·¤ËÂ ·¤æ ¿éÙæß ·¤èçÁ° (1) ÂéÙØæðüçÁÌ Üæ×èÇU °ðçÈ¤çâÜðÙ ÂýçÌÚUæðæ·¤Ìæ çßÁæçÌØ DNA ·ð¤
ÁéÇ¸Ùð âð ¹æð ÎðÌæ ãñU
(2) M¤ÂæÌ´ÚUÁ ·¤è ÂãU¿æÙ ÅðUÅþUæUâæ§UÜèÙ ØéQ¤ ×æØ× ÂÚU ßæüÙ âð ãUæðÌè
ãñU
(3) ÂéÙØæðü»Á °ðçÈ¤çâÜðÙ ØéQ¤ ×æØ× ÂÚU Ìæð ßæüÙ ·¤ÚÔU»æ, Üðç·¤Ù
ÅðUÅþUæâæ§UÜèÙ ØéQ¤ ×æØ× ÂÚU ßæüÙ ÙãUè´ ·¤ÚÔU»æÐ
(4) (1) ÌÍæ (3) ÎæðÙæð´ âãUè ãñU
Öæñ»æðçÜ·¤ ÁæçÌ©UÎ÷ÖßÙ ×ð´ çßçÖóæ æÅUÙæ¥æð´ ·¤æ âßæüçæ·¤ âÖæçßÌ
·ý¤× ãUæð»æ(1) ÁÙçÙ·¤ ¥ÂâÚUæ ® Öæñ»æðçÜ·¤ ¥ßÚUæðæ ® ÁÙçÙ·¤ ÂëÍ·¤·¤ÚUæ
(2) Öæñ»æðçÜ·¤ ¥ßÚUæðæ ® ÁÙçÙ·¤ ¥ÂâÚUæ ® ÁÙçÙ·¤ ÂëÍ·¤·¤ÚUæ
(3) ÁÙçÙ·¤ ÂëÍ·¤·¤ÚUæ ® ÁÙçÙ·¤ ¥ÂâÚUæ ® Öæñ»æðçÜ·¤ ¥ßÚUæðæ
(4) Öæñ»æðçÜ·¤ ¥ßÚUæðæ ® ÁÙçÙ·¤ ÂëÍ·¤·¤ÚUæ ® ÁÙçÙ·¤ ¥ÂâÚUæ
divergence
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·ð¤
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Full Syllabus-IV
10. In which of the following situations would evolution be 10.
slowest for an interbreeding population?
Migration
Selection
Variation
pressure
due to Mutation
(1)
Absent
Low
Low
(2)
Absent
High
High
(3)
High
Low
High
(4)
High
High
Low
11. Homologous organs are
(1) Leg of man, leg of horse, wing of bat
11.
(2) Hand of man, tail to horse, wing of bat
(3) Hand of man, flippers of whale, wing of bat
(4) Head of man, leg of horse, wing of bat
12. Read the following statements -
12.
(i) Multicellular epidermal hair
(ii) Collenchymatous hypodermis
(iii) Pith present
(iv) Vascular bundles present in a ring i.e. eustele
Above given features describe which of the following plant
çÙÙçÜç¹Ì ×ð´ âð ·¤æñÙâè ÂçÚUçSÍçÌ ×ð´ °·¤ ¥ÌÚU ÂýÁÙÙàæèÜ â×çCU
×ð´ ©UÎ÷çß·¤æâ âÕâð æè×æ ãUæð»æÎðàææÌÚ
¿ØÙ ÎæÕ
©UÂçÚUßÌüÙ ·ð¤
·¤æÚUæ çßçÖæÌæ°¡
(1) ¥ÙéÂçSÍÌ
çÙÙ
çÙÙ
(2) ¥ÙéÂçSÍÌ
©Uæ
©Uæ
(3) ©Uæ
çÙÙ
©Uæ
(4) ©U¿
©Uæ
çÙÙ
â×ÁæÌ ¥´» ·¤æñÙâð ãæðÌð ãñU (1) ×æÙß °ß´ ææðÇ¸ð ·ð¤ ÂñÚU ÌÍæ ¿×»æÎÇ¸ ·ð¤ Â´¹
(2) ×æÙß ·¤æ ãUæÍ, ææðÇ¸ð ·¤è Âê¡ÀU, ¿×»æÎÇ¸ ·ð¤ Â´¹
(3) ×ÙécØ ·¤æ ãUæÍ, ÃãðUÜ ·ð¤ çÜÂÚU ÌÍæ ¿×»æÎÇ¸ ·ð¤ Â´¹
(4) ×æÙß ·¤æ çâÚU, ææðÇ¸ð ·ð¤ ÂñÚU ÌÍæ ¿×»æÎÇ¸ ·ð¤ Â´¹
çÙÙ ·¤ÍÙæð´ ·¤æð ÂçÉUØð(i) Õãé·¤æðçàæ·¤èØ ¥çæ¿×èüØ ÚUæð×
(ii) ãUæ§UÂæðÇUç×üâ ·¤æðÜðÙ·¤æ°×æ ØéÌ
(iii) ×Áæ ©UÂçSÍÌ
(iv) âß´ãUÙ ÂêÜ °·¤ ßÜØ ×ð´ ÃØßçSÍÌ Áñâð - ØéSÅUèÜ ×ð´
çÎØð »Øð ©UÂÚUæðÌ Üÿææ ·¤æñÙâð ÂæÎÂ Öæ» ·¤æð ßçæüÌ ·¤ÚUÌð ãñÚ-
parts (1) Monocot stem
(1) °·¤ÕèÁÂæè ÌÙæ
(2) Dicot stem
(2) çmUÕèÁÂæè
(3) Monocot root
(4) Dicot root
13. Which of the following is correct regarding the given figure. 13.
(1) W shows palisade parenchyma having chloroplasts
¹Ö ÂðÚÔU·¤æ°×æ ÂýÎçàæüÌ ·¤ÚUÌæ ãñU Áæð ãUçÚUÌÜß·¤ ØéQ¤ ÌÍæ
ÂÚUÌæð´ ×ð´ ÃØßçSÍÌ ãUæðÌæ ãñU
(2) Z Üæð°× ÂýÎçàæüÌ ·¤ÚUÌæ ãñU
(3) çÎØæ »Øæ ç¿æ çmUÕèÁÂæè Âæü ·¤æ T.S. ÂýÎçàæüÌ ·¤ÚUÌæ ãñU
(4) ©UÂÚUæðÌ âÖè
·¤æÕæðüçÙÈð¤ÚUâ Øé» çÁâ×ð´ ·¤æðØÜð ·¤æ Á×æß ãéU¥æ ßãU ©UÂçSÍÌ Íæ(1) W
arranged in layers
(2) Z shows phloem
(3) The given figure shows T.S. of dicot leaf
(4) All of these
14. Carboniferous period of coal deposition was -
ÌÙæ
(3) °·¤ÕèÁÂæè ×êÜ
(4) çmUÕèÁÂæè ×êÜ
çÎØð »Øð ç¿æ ·ð¤ â´ÎÖü ×ð´ ·¤æñÙâæ âØ ãñU-
14.
(1) 50 mya
(1) 50 mya
(2) 300 mya
(2) 300 mya
(3) 500 mya
(3) 500 mya
(4) 200 mya
(4) 200 mya
/+1
3
15. ............ organise by the Indian Government which will 15. ............ ÖæÚUÌ
Full Syllabus-IV
of introducing ....................... for public services.
âÚU·¤æÚ mUæÚUæ çÙç×üÌ â´»ÆUÙ Áæð ç·¤ ........ ¥Ùéâ´ææÙ
â´Õ´ æè ·¤æØæðZ ·¤è ßñææçÙ·¤Ìæ ÌÍæ ÁÙ âðßæ¥æð´ ·ð¤ çÜ° .......................
·ð¤ âçóæßðàæ ·¤è âéÚUÿææ ¥æÎè ·ð¤ ÕæÚÔU ×ð´ çÙæüØ ÜðÌè ãñU
(1) GEAC, GM GM-organisms
(1) GEAC, GM GM-organisms
(2) GM, GEAC, GM-organisms
(2) GM, GEAC, GM-organisms
(3) GEAC, GM-organisms, GM
(3) GEAC, GM-organisms, GM
(4) GEAC, GM-organisms, Biopiracy
(4) GEAC, GM-organisms, Biopiracy
make regarding the validity of ........ research and the safety
16. Which of the following characters is not shown by the mem- 16.
bers of class Chondrichthyes (1) Notochord is persistenet throughout life
(2) Gill slits are separate and without operculum
(3) The skin is tough containing minute placoid scales
(4) Air bladder present for buoyancy
17. Assertion :- At the end of juvenility, the organism develops 17.
the capacity to reproduce.
Reason :- It represents the time period between the first
and next flowering in plants
(1) If both A and R are true and R is correct explanation
of A
(2) If both A & R are true but R is not correct explanation
of A
(3) If A is true and R is wrong
(4) If A and R both are wrong
18. Dosa and Idli are fermented preparation of rice and Black 18.
Gram. The fermentation is done with
(1) Leuconostoc
(2) Streptococus
(3) Saccharomyces
(4) More than one option is correct
19. Read the given statements and select the correct ones (i) Root caps are present in prop roots
(ii) Pneumatophores help to get oxygen for respiration
(iii) Edible part of ginger is underground stem
(iv) Hydrophytes usually possess a well developed root
19.
çÙ×A ×ð´ âð ·¤æñÙâæ Üÿææ ·¤æðçÇþUÍèÁ ß»ü ·ð¤ âÎSØæð´ mUæÚUæ ÎàææüØæ ÁæÌæ
ãñU(1) ÂëDUÚUæê ¥æÁèßÙ ÕÙæ ÚUãUÌæ ãñUÐ
(2) Üæð× ÎÚUæÚÔÚ ÂëÍ·¤ ÌÍæ ¥æðÂÚU·¤êÜ× ÚUçãUÌ ãUæðÌè ãñU
(3) ß¿æ âêÿ× Üð·¤æð§UÇU àæË·¤æð´ ØéQ¤ ß ¹éÚUÎÚUè ãUæðÌè ãñU
(4) ©Üæß·¤Ìæ ÂýÎæÙ ·¤ÚUÙð ãðUÌé ßæÌæàæØ ©UÂçSÍÌ
·¤ÍÙ : ç·¤àææðÚU ¥ßSÍæ ·ð¤ â×æ# ãUæðÙð ÂÚU Áèßæð´ ×ð´ ÁÙÙ ·¤è ÿæ×Ìæ
çß·¤çâÌ ãUæðÌè ãñUÐ
·¤æÚUæ : ØãU ÂæÎÂæð ×ð´ ÂýÍ× ¥æñÚU ¥»Üð ÂécÂÙ ·ð¤ ×Ø ·ð¤ â×Ø ·¤æð
ÂýÎçàæüÌ ·¤ÚUÌè ãñUÐ
(1) ·¤ÍÙ ¥æñÚU ·¤æÚUæ ÎæðÙæð´ âãUè ãñÚ ¥æñÚU ·¤æÚUæ, ·¤ÍÙ ·¤æ âãUè
SÂCUè·¤ÚUæ ÎðÌæ ãñUÐ
(2) ·¤ÍÙ ¥æñÚU ·¤æÚUæ ÎæðÙæð´ âãUè ãñÚ ç·¤Ìé ·¤æÚUæ, ·¤ÍÙ ·¤æ âãUè
SÂCUè·¤ÚUæ ÙãUè´ ÎðÌæ ãñUÐ
(3) ·¤ÍÙ âãUè ãñU ç·¤Ìé ·¤æÚUæ »ÜÌ ãñUÐ
(4) ·¤ÍÙ ß ·¤æÚUæ ÎæðÙæð´ ¥âØ ãñU´Ð
§UÇUÜè ÌÍæ ÇUæðâæ, ¿æßÜ ÌÍæ ©UÇ¸Î ·¤è ÎæÜ ·ð¤ ç·¤ßæ âð ÌñØæÚU ãUæðÌð
ãñÚÐ ØãU ç·¤ßæ ç·¤Øæ ÁæÌæ ãñU(1) ËØê·¤æðÙæðSÅUæò·¤ mUæÚUæ
(2) SÅþðUÅUæð·¤æð·¤â mUæÚUæ
(3) âð·ð¤ÚUæð×æ§UçâÁ mUæÚUæ
(4) °·¤ âð ¥çæ·¤ çß·¤ËÂ âãUè ãñU
çÎØð »Øð ·¤ÍÙæð´ ·¤æð ÂçÉUØð ÌÍæ âãUè ·¤æ ¿ØÙ ·¤èçÁ° (i) ¥ßSÌÖ ×êÜ ×ð´ ×êÜ»æðÂ ©UÂçSÍÌ ãUæðÌæ ãñU
(ii) Øê×ðÅUæðÈ¤æðÚUâ àßâÙ ·ð¤ çÜ° ¥æòâèÁÙ ÂýæçÌ ×ð´ âãUæØ·¤ ãUæðÌð ãñÚ
(iii) ¥ÎÚU·¤ ·¤æ ¹æÙð ØæðØ Öæ» Öêç×»Ì ÌÙæ ãUæðÌæ ãñU
(iv) ÁÜæðÎçÖÎ ×ð´ âæ×æØÌØæ âéçß·¤çâÌ ×êÜ Ì´æ ÂæØæ ÁæÌæ ãñU
system
(1) i and ii
(2) ii and iii
(1) i ÌÍæ ii
(2) ii ÌÍæ iii
(3) i, ii and iii
(4) i, ii, iii and iv
(3) i, ii ÌÍæ iii
(4) i, ii, iii ÌÍæ iv
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Full Syllabus-IV
20. In Trygon, the mouth is located ventrally and the teeth are 20.
modified scales, which are (1) Forwardly directed
(2) Backwardly directed
(3) Sparsely arranged
(4) None of these
21. It is said that Mendel proposed that the factor controlling 21.
any character is discrete and independent. This proposition
was based on the (1) Result of F3 generation of a cross
(2) Observations that the offspring of a cross made between
plants having two contrasting characters shows only one
character without any blending
(3) Self pollination of F1 offspring
(4) Cross pollination of parental generations
22. Select the odd one out w.r.t. chormosomal theory of 22.
inheritance (1) Both gene pairs and chromosomal pairs are segregated
during gametogenesis
(2) Behaviour of chromosomes is parallel to behaviour of
genes
ÅUþæ§U»æðÙ ×ð´ ×é¹ ¥æÚU çSÍçÌ ×ð´ ÂæØæ ÁæÌæ ãñU ÌÍæ Îæ¡Ì M¤ÂæÌçÚUÌ àæË·¤
ãUæðÌð ãñÚ Áæð ãUæðÌð ãñÚ (1) ¥æ»ð ·¤è ¥æðÚ ©U×é¹
(2) ÂèÀðU ·¤è ¥æðÚU ©U×é¹
(3) çÕ¹ÚÔU ãéUØð
ØãU ·¤ãUæ ÁæÌæ ãñU ç·¤ ×ðÇUÜ Ùð ÂýçÌÂæçÎÌ ç·¤Øæ ç·¤ ç·¤âè Üÿææ ·¤æð
çÙØ´çæÌ ·¤ÚUÙð ßæÜæ ·¤æÚU·¤ ÂëÍ·¤ ÌÍæ SßÌ´æ ãUæðÌæ ãñUÐ ØãU ÂýSææßÙæ
¥æææçÚUÌ Íè (1) ç·¤âè ·ý¤æòâ ×ð´ F3 ÂèÉUè ·ð¤ ÂçÚUææ×æð´ ÂÚU
(2) §Uâ ¥ßÜæð·¤Ù ÂÚU ç·¤ Îæð çßÂØæüâè Üÿææ ÎàææüÙð ßæÜð ÂæÎÂæð´ ·ð¤
×Ø ·ý¤æòâ âð ©UÂÙ â´ÌçÌ çÕÙæ ç·¤âè ç×ææ ·ð¤ ·ð¤ßÜ °·¤ Üÿææ
ÎàææüÌè ãñU
(3) F1 â´ÌçÌØæð´ ·¤æ SßÂÚUæ»æ
(4) ÂñÌë·¤ ÂèçÉUØæð´ ·¤æ ÂÚUÂÚUæ»æ
¥æÙéßæ´çàæ·¤Ìæ ·ð¤ »éæâêæèØ çâhUæÌ ·ð¤ â´ÎÖü ×ð´ çßá× ·¤æ ¿ØÙ
·¤èçÁ°(1) Øé×·¤ÁÙÙ ·ð¤ ÎæñÚUæÙ ÁèÙ Øé× ÌÍæ »éæâêæ Øé× ÎæðÙæð´ ÂëÍ·¤ ãUæðÌð
ãñÚ
(2) »éæâêææð´ ·¤æ ÃØßãUæÚU ÁèÙæð´ ·ð¤ ÃØßãUæÚU ·ð¤ â×æÌÚU ãUæðÌæ ãñ
çmU»éçæÌ ÌÍæ ¥»éçæÌ ·¤æðçàæ·¤æ¥æð´ ×ð´ ·ý¤×àæÑ »éæâêæ ÌÍæ ÁèÙ
Øé×æð´ ×ð´ ÂæØð ÁæÌð ãñÚÐ
(4) çÙáð¿Ù ·ð¤ ÎæñÚUæÙ »éæâêææð´ ÌÍæ ×ðÇUðçÜØÙ ·¤æÚU·¤æð´ ·¤è Øéç×Ì
¥ßSÍæ ÂéÙÑ SÍæçÂÌ ãUæð ÁæÌè ãñUÐ
°·¤ ÂæÎÂ ×ð´ ÁèÙ C ÌÍæ P ÂécÂ ·ð¤ ÙèÜð ÚÚ» ·¤æð Âý·¤ÅU ·¤ÚUÙð ·ð¤ çÜ°
¥æßàØ·¤ ãñUÐ ØçÎ ÎæðÙæð´ ×ð´ âð ·¤æð§üU âè æè ÁèÙ Øæ ÎæðÙæð´ ãUè Áèâ Âêæü
M¤Â âð ¥ÂýÖæßè ¥ßSÍæ ×ð´ ¥æ ÁæÌè ãñU Ìæð ÂécÂ ·¤æ ÚÚ» Õñ´»Ùè ãUæðÌæ ãñÐ
çÙæ ×ð âð ç·¤â ·ý¤æòâ âð 75% Õñ́»Ùè ÌÍæ 25% ÙèÜð ÂécÂ ßæÜè
âÌçÌØæ¡ Âýææ ãUæð»è?
(3)
(3) Chromosomes and genes occur in pairs in diploid and
haploid cells respectively
(4) The paired condition of both choromosomes as well as
Mendelian factors is restored during fertilization
23. In a plant gene C and P essential to produce Blue colour. 23.
When either C or P or both gene occur in recessive condition
then flower colour is purple, which of the following cross
produce 75% purple and 25% Blue flowered offspring ?
(1) CCPP x ccpp
(2) CcPp x ccpp
(1) CCPP x ccpp
(2) CcPp x ccpp
(3) CcPp x Ccpp
(4) ccpp x ccpp
(3) CcPp x Ccpp
(4) ccpp x ccpp
24. Morgan carried out several dihybrid crosses in Drosophila 24.
& discovered Linkage. He observed that :(1) Genes which were tightly linked showed higher recom.
bination.
(2) Genes of white eyes & yellow body in Drosophila were
tightly linked & showed 1.3% recombination
(3) Genes which were loosely linked showed higher linkage.
(4) Genes of white eyes & miniature wings in Drosophila
showed 37.2% linkage
/+1
×æð»üÙ Ùð ÇþUæðâæðçÈ¤Üæ ×ð´ ·¤§üU çmUâ´·¤ÚU ·ý¤æòâ ç·¤° ÌÍæ âãUÜÙÌæ ·¤è
¹æðÁ ·¤èÐ ©UãUæð´Ùð Îð¹æ ç·¤ (1) ÁèÙ Áæð ×ÁÕéÌè âð âãUÜÙ ãUæðÌð ãñÚ, ©U¿ ÂéÙØæðüÁÙ ÎàææüÌð ãñ´
ÇþUæðâæðçÈ¤Üæ ×ð´ âÈð¤Î ¥æ´¹æð´ ß ÂèÜð àæÚUèÚU ·ð¤ ÁèÙ ×ÁÕêÌè âð
âãUÜÙ ãUæðÌð ãñÚ ÌÍæ 1.3% ÂéÙØæðüÁÙ ÎàææüÌð ãñÚ
(3) ÁèÙ Áæð çàæçÍÜ M¤Â âð âãUÜÙ ãUæðÌð ãñÚ, ©U¿ âãUÜÙ ÎàææüÌð ãñÚ
(2)
(4) ÇþUæðâæðçÈ¤Üæ ×ð́ âÈð¤Î ¥æ´¹æð́ ß ÀUæðÅðU Â´¹æð́ ·ð¤ ÁèÙ 37.2% âãUÜÙÌæ
ÎàææüÌð ãñÚ
5
Full Syllabus-IV
25. Two genes are located on the same chromosome and are 25. Îæð ÁèÙ â×æÙ »éæâêæ ÂÚU ©UÂçSÍÌ ãñU ÌÍæ °·¤ ÎêâÚÔU âð 12 ×æÙç¿æ
known to be 12 map units apart. An AABB individual is
§U·¤æ§üU ÎêÚU ãñUÐ °·¤ AABB ÃØçæ ·¤æ â´·¤ÚUæ aabb ÃØçæ âð ·¤ÚUßæÙð
crossed to an aabb individual to produce AaBb offspring.
ÂÚU AaBb â´ÌÌè ÕÙÌè ãñUÐ AaBb â´ÌÌè ·¤æ ·ý¤æòâ aabb ÃØçæ âð
The AaBb offspring are then crossed to aabb individuals. If
·¤ÚUßæÙð ÂÚU 1000 â´ÌÌè ÕÙæÌð ãñU, Ìæð çÙÙ ¿æÚU ÁèÙ ÂýæM¤Â AaBb,
this cross produces 1000 offspring, what are the predicted
Aabb, aaBb ÌÍæ aabb ßæÜè â´ÌÌèØæð́ ·¤è ¥Ùé×æÙèÌ â´Øæ ãUæð»è ?
numbers of offspring with each of the four genotypes :
AaBb, Aabb, aaBb and aabb ?
(1) 60 Aabb, 440 aaBb, 440 AaBb and 60 aabb
(1) 60 Aabb, 440 aaBb, 440 AaBb ÌÍæ 60 aabb
26. How many of the labelled structures are diploid in ploidy 26.
w.r.t. the following diagram -
(1) Four
(2) Five
(3) Six
çÙ×Aæ´ç·¤Ì ç¿æ ·ð¤ â´ÎÖü ×ð´ Ùæ×æ´ç·¤Ì âÚÚ¿Ù¥æð´ ×ð´ ç·¤ÌÙè â´ÚU¿Ùæ°´
»éçæÌæ ×ð´ çmU»éçæÌ ãñU-
(1) ¿æÚU
(4) One
27. X-bodies are two darkly stained bodies present in cytoplasm 27. X-·¤æØ
of (1) Synergid cell before entry of pollen tube
(2) Degenerated synergid cell after entry of pollen tube
(3) Embryo sac before entry of pollen tube
(4) Pollen tube before germination
28. Which one is an albuminous dicot seed ?
28.
(1) Castor
(2) Barley
(3) Pea
(4) More than one option is correct
29.
29. Perisperm represents (1) Remains of nucellus
(2) Glandular cells of inner integument
(3) Glandular cells at the micropylar end of funiculus
(4) Lignified cells at the base of embryo sac
/+1
(2) Âæ¡¿
(3) ÀUÑ
(4) °·¤
Îæð »ãUÚUè ÚÚçÁÌ â´ÚU¿Ùæ°ð´ ç·¤â·ð¤ ·¤æðçàæ·¤æ ÎýÃØ ×ð´ ©UÂçSÍÌ
ãUæðÌè ãñU (1) ÂÚUæ» ÙçÜ·¤æ ·ð¤ Âýßðàæ ·ð¤ Âêßü âãUæØ·¤ ·¤æðçàæ·¤æ¥æð´ ×ð´
(2) ÂÚUæ» ÙçÜ·¤æ ·ð¤ Âýßðàæ ·ð¤ Âà¿æÌ÷ âãUæØ·¤ ·¤æðçàæ·¤æ¥æð´ ×ð
(3) ÂÚUæ» ÙçÜ·¤æ ·ð¤ Âýßðàæ âð Âêßü Öýêæ·¤æðàæ ×ð´
(4) ¥´·é¤ÚUæ âð Âêßü ÂÚUæ» ÙçÜ·¤æ ×ð´
çÙÙ ×ð´ âð ·¤æñÙâæ ÖýêæÂæðáè çmUÕèÁÂæè ÕèÁ ãñU ?
(1) ¥ÚUÇU
(2) Áæñ´
(3) ×ÅUÚU
(4) °·¤ âð ¥çæ·¤ çß·¤ËÂ âãUè ãñU
ÂçÚUÖýêæÂæðá ÂýÎçàæüÌ ãæðÌæ ãñU (1) ÕèÁæÇU·¤æØ ·¤ð ¥ßàæðá
(2) ¥æÌçÚU·¤ ¥ØæßÚUæ ·¤è »ý´çÍÜ ·¤æðçàæ·¤æ°´
(3) ÕèÁæÇU ßëÌ ·ð¤ ÕèÁæÇU mUæÚèUØ çâÚÔU ·¤è ¥æðÚ ©UÂçSÍÌ »ý´çÍÜ
·¤æðçàæ·¤æ°ð´ U
(4) Öýêæ·¤æðá ·ð¤ ¥æææÚU ÂÚU ©UÂçSÍÌ çÜçÙ·ë¤Ì ·¤æðçàæ·¤æ°ð´
6
Full Syllabus-IV
30. Vegetarians some time suffer from protein deficiency, because 30.
(1) most plant proteins are incomplete
(2) most animal proteins are incomplete
(3) all animal proteins are incomplete
(4) dietry protein provide only nonessential amino acids
31. A messenger RNA molecule for making a protein is made 31.
in the nucleus and sent out to a ribosome. The ribosome
reads the mRNA message and makes the mRNA message
and makes a protein containing 120 amino acids. The mRNA
consisted of at least how many codons?
(1) 30
(2) 121
(3) 120
àææ·¤æãUæÚUè ·¤§üU ÕæÚU ÂýæðÅUèÙ ·¤è ·¤×è âð »ýSÌ ÚUãUÌð ãñÚ, Øæð´ç·¤ ÂæÎÂ ÂýæðÅUèÙ ¥Âêæü ãUæðÌè ãñU
(2) ¥çæ·¤æ´àæ ÁÌé ÂýæðÅUèÙ ¥Âêæü ãUæðÌè ãñU
(3) â×SÌ ÁÌé ÂýæðÅUèÙ ¥Âêæü ãUæðÌè ãñU
(4) ¥æãUæÚU ÂýæðÅUèÙ ·ð¤ßÜ ¥ÙæçÙßæØü ¥×èÙæð ¥Ü ÂýÎæÙ ·¤ÚUÌè ãñU
°·¤ â´ÎðàæßæãU·¤ RNA ·¤æ çÙ×æüæ ÂýæðÅUèÙ ÕÙæÙð ·ð¤ çÜ° ·ð¤Îý·¤ ×ð´
ç·¤Øæ »Øæ ÌÍæ °·¤ ÚUæ§UÕæðâæð× ·ð¤ çÜ° ÖðÁæ »ØæÐ ÚUæ§UÕæðâæð× Ùð
mRNA ·ð¤ â´Îðàæ ·¤æð ÂÉ¸Uæ ÌÍæ °·¤ ÂýæðÅUèÙ ·¤æ çÙ×æüæ çÁâ×ð´ 120
¥×èÙæð ¥Ü Íð Ìæð mRNA ×ð´ Ü»Ö» ç·¤ÌÙð ·¤æðÇUæðÙ ©UÂçSÍÌ Íð -
(1) ¥çæ·¤æ´àæ
(1) 30
(4) 360
(2) 121
(3) 120
(4) 360
(d) Energy flow is the functional attributs of biotic community
ßáæü ßÙæð´ ·ð¤ âÎ´Öü ×ð´ »ÜÌ ·¤ÍÙ ·¤è ÂãU¿æÙ ·¤èçÁØð (a) ßáæü ßÙæð´ ·ð¤ ·ý¤æçÌ·¤ ØæðÁ·¤ ÁæçÌØæð´ ·¤è ÕæãéUËØÌæ ãñUÐ
(b) ßáæü ßÙæð´ ×ð´ ×æñâ×è ÂçÚUßÌüÙ ·¤× ãUæðÌð ãñUÐ
(c) ßæçáü·¤ ßÜØ SÂcÅUÌØæ çÎ¹æ§üU ÎðÌè ãñUÐ
(d) ª¤Áæü ÂýßæãU Áñçß·¤ â×éÎæØ ·¤æ ·¤æØæü×·¤ Üÿææ ãñUÐ
(1) a,b
(2) c,d
(1) a,b
(2) c,d
(3) only c
(4) a & d
(3) ·ð¤ßÜ c
(4) a & d
32. Find out the wrong statement regarding tropical rain forest- 32.
(a) Critical link species are abudance in tropical rain forest
(b) Tropical rain forest has less seasonal variation
(c) Annual rings are visible distinctly.
33. The effective biocontrol agent of several plant pathogen is 33.
(1) Bacillus thuringiensis
(2) Ladybird beetle
(3) Trichoderma
(4) Baculovirus
34. The life cycle pattern, in which the diploid sporophyte is 34.
dominant, photosynthetic & independent phase of plant.
The gametophyte phase is represented by the single to
few celled haploid gametophyte. This type of life cycle
¥Ùð·¤ ÂæÎÂ ÚUæð» ÁÙ·¤æð´ ·ð¤ çÜ° ÂýÖæßè Áñß çÙØ´æ·¤ ·¤æÚU·¤ ãñU (1) ÕðçâÜâ ÍêÚUèçÁ°´çââ
(2) ÜðÇUèÕÇüU çÕÅUÜ
(3) ÅþUæ§U·¤æðÇU×æü
(4) Õð·é¤Üæðßæ§UÚUâ
ÁèßÙ ¿·ý¤ ÂýçÌM¤Â çÁâ×ð´ ÂæÎÂ ·¤è çmU»éçæÌ ÕèÁææéÎ÷çÖÎ ÂèÉ¸Uè
ÂýÖæßè, Âý·¤æàæ â´àÜðáè ¥æñÚU SßÌ´æ ¥ßSÍæ ãUæðÌè ãñUÐ Øé×·¤æðÎ÷çÖÎ
¥ßSÍæ, °·¤ âð ·é¤ÀU ¥·¤æðçàæ·¤èØ ¥»éçæÌ Øé×·¤æðÎ÷çÖÎ mUæÚUæ ÂýÎçàæüÌ
ãUæðÌè ãñUÐ ØãU ÂýçÌM¤Â ÂæØæ ÁæÌæ ãñU -
pattern is found in (1) ·ð¤ßÜ ÅñUçÚUÇUæðÈ¤æ§UÅ÷Uâ ×ð´
(1) Only pteridophytes
(2) Only gymnosperms
(2) ·ð¤ßÜ çÁÙæðSÂ×ü ×ð´
(3) Only angiosperms
(3) ·ð¤ßÜ °´çÁØæðSÂ×ü ×ð´
(4) All seed bearing plants
(4) âÖè
35. Which of the following is heterosporous plant ?
(1) Funaria
(2) Equisetum
(3) Selaginella
(4) Polytrichum
36. The effects of 'Green Revolution' includes (1) Low disease resistance
(2) High yield but poor nutrient contents
(3) Water logging and soil salinity
(4) Desertification and low pest resistance
/+1
35.
36.
ÕèÁææÚUè ÂæÎÂæð´ ×ð´
çÙÙ ×ð´ âð çßá×ÕèÁææé·¤ ÂæÎÂ ãñU ?
(1) ØêÙðçÚUØæ
(2) §UßèâèÅU×
(3) çâÜðçÁÙðÜæ
(4) ÂæòÜèÅþUæ§U×
ÒãUçÚUÌ ·ý¤æ´çÌÓ ·ð¤ ÂýÖæßæð´ ×ð´ âç×çÜÌ ãñU (1) ·¤× ÚUæð» ÂýçÌÚUæðæ·¤Ìæ
(2) ©Uæ ©UÂæÎ·¤Ìæ ç·¤Ìé ·¤× Âæðá·¤ ×æææ
(3) ÁÜ çÙ×ÙÌæ ÌÍæ ×ëÎæ ÜßæÌæ
(4) ×M¤SÍÜè·¤ÚUæ ÌÍæ ·¤× ÂèÇ¸·¤ ÂýçÌÚUæðæ·¤Ìæ
7
Full Syllabus-IV
37. Identify the following figure of an alga and tell its life cycle 37.
çÙÙ àæñßæÜ ·¤æð ÂãU¿æçÙ° ¥æñÚU §Uâ·¤æ ÁèßÙ ¿·ý¤ ÂýçÌM¤Â ÕÌæ§U° -
pattern -
(1) Øê·¤â
- çÇUÜæð´çÅU·¤
(2) Øê·¤â - ãðUÜæð´çÅU·¤
(3) çÇUçÅU¥æðÅUæ - çÇUÜæð´çÅU·¤
(4) ÂæðÚUÈ¤æØÚUæ - çÇUÜæð´çÅU·¤
(1) Fucus - Diplontic
(2) Fucus - Haplontic
(3) Dictyota - Haplontic
(4) Poryphyra - Diplontic
38. Which of the following enzymes is correctly matched to its 38.
function?
¥ææðçÜç¹Ì ×ð´ âð ·¤æñÙ §Uâ·ð¤ ·¤æØü ·ð¤ âæÍ âãUè ç×ÜæÙ ãñU(1) ãðUÜè·ð¤Á °·¤ ÚUæé·¤è DNA ·¤æ SÍæÂÙ
(1) Helicases stablize single-stranded DNA
(2) ÅUæðÂæð¥æ§Uâæðç×ÚÔUÁ ØêçÜ¥æðÅUæ§UÇU ·ð¤ ×Ø Õ´ææð́ ·¤æð ÌæðÇ¸Ùæ
(2) Topoisomerases break bonds between nucleotides
(3) DNA Üæ§U»ðÁ ÂÀðUÌè ÚUæé ×ð´ ØêçÜ¥æðÅUæ§UÇUæð´ ·¤æð ÁæðÇ¸Ùæ
(3) DNA ligase adds nucleotides to the lagging strand
(4) DNA ÂæðÜè×ÚÔUÁ-II
(1) Only a
(2) a, b
¥æð·¤æÁæ·¤è ¹ÇUæð´ ·ð¤ ×Ø ¥ß·¤æàæ ·¤æð
ÖÚUÙæ
°·¤ ÕðÜÙæ·¤æÚU ÂæçàßüØ àææ¹æ Áæð ×éØ ¥ÿæ ·ð¤ ¥æææÚU âð ©UÂóæ ãUæðÌè
ãñU ÌÍæ ·é¤ÀU â×Ø Ì·¤ ßæØé ×ð´ ßëçhU ·¤ÚUÙð ·ð¤ Âà¿æÌ÷ Ùè¿ð ·¤è ¥æðÚU
Ûæé·¤·¤ÚU Öêç× âÌãU ·¤æð SÂàæü ·¤ÚUÌè ãéU§üU ¿æÂ ÕÙæÌè ãñU(1) ÂæðçÎÙæ ÌÍæ ¥Ùæóææâ
(2) »éÜÎæ©UÎè
(3) ÂèçSÅUØæ ÌÍæ ·ð¤Üæ
(4) ¿×ðÜè
ç·¤S×æð´ ·ð¤ â´Îæü ×ð´ ¥âé×ðçÜÌ ·¤è ÂãU¿æÙ ·¤èçÁØð È¤âÜ
ç·¤S×
(1) ÜæðçÕØæ

Âêâæ Sßçæü×
(2) ç×¿ü

Âêâæ âÎæÕãæUÚ
(3) Èê¤Ü»æðÖè

Âêâæ àæéÖýæ
(4) »ð´ãêU

çãU×ç»ÚUè
çÙÙ ×ð´ âð ·¤æñÙâæ âãUè ãñU (a) ¥·¤æÕüçÙ·¤ ÂÎæÍü → ·¤æÕüçÙ·¤ ÂÎæÍü Ñ ©UÂæÎ·¤
(b) ÁçÅUÜ ·¤æÕüçÙ·¤ ÂÎæÍü → âÚUÜ ·¤æÕüçÙ·¤ ÂÎæÍü Ñ ¥ÂæÅU·¤
(c) ÂæÎÂ ÂÎæÍü → ÁÌé ÂÎæÍü : àææ·¤æãUæÚUè
(d) ÚUæâæØçÙ·¤ ª¤Áæü → ª¤c×æ ª¤Áæü : ©UÂÖæðææ
(1) ·ð¤ßÜ a
(2) a, b
(3) a, b, c
(4) a, b, c, d
(3) a, b, c
(4) DNA polymerase-II closes gaps between Okazaki
fragments
39. A slender lateral branch arises from the base of the main 39.
axis and after growing aerially for some time arch
downwards to touch the ground in (1) Mint and pineapple
(2) Chrysanthemum
(3) Pistia and banana
(4) Jasmine
40. Select the incorrect match w.r.t. variety Crop
Variety
(1) Cowpea

Pusa Swarnim
(2) Chilli

Pusa sadabahar
(3) Cualiflower

Pusa Shubhra
(4) Wheat

Himgiri
41.
41. Which is/are correct (a) Inorganic matter → organic matter : producer
(b) Complex organic matter → Simple organic : Decomposer
(c) Plant material → Animal material : Herbivores
(d) Chemical energy → Heat energy : Consumers
/+1
40.
(4) a, b, c, d
8
Full Syllabus-IV
(1) Only b
(2) a, b
çÙÙ ×ð´ âð ·¤æñÙâæ ·¤ÍÙ âØ ãñU (a) Áñçß·¤ ÌÍæ ¥Áñçß·¤ æÅU·¤æð´ ·¤è ÂÚUSÂÚU ç·ý¤Øæ¥æð´ ·ð¤ È¤ÜSßM¤Â
°·¤ ÖæñçÌ·¤ â´ÚU¿Ùæ çß·¤çâÌ ãUæðÌè ãñU, Áæð ÂýØð·¤ Âý·¤æÚU ·ð¤ â×éÎæØ ·¤è
çßçàæCUÌæ ãñUÐ
(b) Áñçß·¤ ÌÍæ ¥Áñçß·¤ æÅU·¤æð´ ·¤è ÂÚUSÂÚU ç·ý¤Øæ¥æð´ ·ð¤ È¤ÜSßM¤Â
°·¤ ÖæñçÌ·¤ â´ÚU¿Ùæ çß·¤çâÌ ãUæðÌè ãñU, Áæð ÂýØð·¤ Âý·¤æÚU ·ð¤ ÂçÚUÌ´æ ·¤è
çßçàæCUÌæ ãñUÐ
(c) Áñçß·¤ ÌÍæ ¥Áñçß·¤ æÅU·¤æð´ ·¤è ÂÚUSÂÚU ç·ý¤Øæ¥æð´ ·ð¤ È¤ÜSßM¤Â
°·¤ ÖæñçÌ·¤ â´ÚU¿Ùæ çß·¤çâÌ ãUæÌð è ãñU, Áæð ÂýØð·¤ Âý·¤æÚU ·ð¤ ÂæçÚUçSÍçÌ·¤è
·¤è çßçàæCUÌæ ãñUÐ
(d) Áñçß·¤ ÌÍæ ¥Áñçß·¤ æÅU·¤æð´ ·¤è ÂÚUSÂÚU ç·ý¤Øæ¥æð´ ·ð¤ È¤ÜSßM¤Â
°·¤ ÖæñçÌ·¤ â´ÚU¿Ùæ çß·¤çâÌ ãUæðÌè ãñU, Áæð ÂýØð·¤ Âý·¤æÚU ·ð¤ ÁÙâ´Øæ
·¤è çßçàæCUÌæ ãñUÐ
(1) ·ð¤ßÜ b
(2) a, b
(3) a, c, d
(4) b, c, d
(3) a, c, d
42. Which is/are correct -
42.
(a) Interaction of biotic and abiotic components result in a
physical structure that is characteristic for each type of
community.
(b) Interaction of biotic and abiotic components result in a
physical structure that is characteristics for each ecosystem.
(c) Interaction of biotic and abiotic component result in a
physical structure that is characteristics of ecology.
(d) Interaction of biotic and abiotic component result in a
physical structure that is characteristics of population.
(4) b, c, d
generation. Percentage of bacteria with radioactive DNA is
§üU. ·¤æðÜæ§üU ·ð¤ °·¤ ÚÔUçÇUØæð °çÅUß DNA ¥æé ·¤æð °·¤ ÙæòÙ-ÚÔUçÇUØæð°çÅUß
×æØ× ×ð´ Îæð ÂèçÉ¸UØæð´ Ì·¤ ÂýçÌ·ë¤çÌ ·¤ÚUßæØæ, Ìæð ¥Õ ÚÔUçÇUØæð°çÅUß
DNA ·¤è ÂýçÌàæÌ ×æææ ãUæð»è-
(1) 100%
(2) 50%
(1) 100%
(2) 50%
(3) 25%
(4) 12.5%
(3) 25%
(4) 12.5%
43. Escherichia coli with completely radioactive DNA was 43.
allowed to replicate in non-radioactive medium for two
44. Which of the following pairs is not correctly matched -
44.
(1) ATP The principal energy carrying compound in the cell
(2) Purine Nitrogenous base cytosine, thymine and uracil
(3) r-RNA RNA molecules found in ribosomes
(4) Recombination DNA formed by joining of segment
DNA of DNA from different sources
45. Following statements explain reproduction in animals (a) Sperm enters the ovum chemically
(b) Gametes are formed from epithelial tissues
(c) Gametes are formed from connective tissues
(d) Most land animals, both vertebrate and invertebrate,
use internal fertilisation.
(e) At the onset of puberty humans produce increasing
amounts of the hormone FSH, which induces maturation
45.
fuEu esa ls dkSulk ;qXe lgh feyku ugha gS&
(1) ATP dksf'kdk dk eq[; ≈tkZ LFkkukUrjh ;kSfxd
(2) I;wjhu ukbV™kstuh {kkj lkbVksflu] Fkk;feu rFkk ;wjsfly
(3) r-RNA jkbckslkse esa feyus okyk RNA v.kq
(4) iqu;ksZtu ,d DNA [k.M ds vU; lzksr ds DNA ls tqM+us ij
izkIr DNA
çÙÙçÜç¹Ì ·¤ÍÙ ÁÌé¥æð´ ×ð´ ÁÙÙ ·¤è ÃØæØæ ·¤ÚUÌð ãñU´(a) àæé·ý¤ææé ¥ÇðU ×ð´ ÚUæâæØçÙ·¤ ÌÚUè·ð¤ âð Âýßðàæ ·¤ÚUÌæ ãñU
(b) Øé×·¤æð´ ·¤æ çÙ×æüæ ©UÂ·¤Üæ ©Uæ·¤æð´ âð ãUæðÌæ ãñU
(c) Øé×·¤æð´ ·¤æ çÙ×æüæ â´ØæðÁè ©Uæ·¤æð´ âð ãUæðÌæ ãñU
(d) ¥çæ·¤æ´àæ ·¤àæðM¤·¤è ÌÍæ ¥·¤àæðM¤·¤è SæÜèØ ÁÌé, ¥æÌçÚU·¤
çÙáð¿Ù ·¤ÚUÌð ãñÚ
(e) ØæñßÙæßSÍæ ·ð¤ ¥æÚUÖ ãUæðÙð ÂÚU ×ÙécØæð´ ×ð´ FSH ·¤æ ©UÂæÎÙ ÕÉ¸UÙð
Ü»Ìæ ãñU Áæð ÙÚUæð´ ×ð´ ÚÔUÌæ ÙçÜ·¤æ¥æð´ ·ð¤ ÂçÚUÂßÙ ·¤æð ÂýðçÚUÌ ·¤ÚUÌæ ãñU
of seminiferous tubules in males.
How many satatements are true of these
(1) three
(2) four
(3) five
(4) two
/+1
§UÙ×ð´ âð ç·¤ÌÙð ·¤ÍÙ âØ ãñU(1) ÌèÙ
(2) ¿æÚU
(3) Âæ¡¿
(4) Îæð
9
Full Syllabus-IV
ceive -
çÁÙ çSæØæð ×ð´ »ÖæüææÙ ·¤è â×SØæ ÚUãUÌè ãñU ©UÙ·¤è âãUæØÌæ ·ð¤
çÜ°..........................âð ÕÙÙð ßæÜð Öýêææð´ ·¤æð Öè SÍæÙæÌÚUæ ·ð¤
çÜ° ÂýØæð» ×ð´ ÜæØæ Áæ â·¤Ìæ ãñU-
(1) In-vivo fertilization
(1) In-vivo fertilization
(2) Parthenogenesis
(2) Parthenogenesis
(3) Both (1) and (2)
(3) Both (1) and (2)
(4) None
(4) ·¤æð§üU
46. Embryos formed by ...................also could be used for 46.
such transfer to assist those females who cannot con-
47. Study the following statements -
47.
(a) Ecology at the organismic level is essentially physiological
ecology.
(b) Ecosystem is a structural unit of landscape.
(c) Landscape is a structural unit of ecosystem.
(d) Ecology at the organism level is essentially genetic
ecology.
(1) c & d are correct
(2) b & d are correct
(3) c & d are incorrect
(4) a & b are correct
48. (a) Pyramid of Number deals with number of individuals in 48.
an particular area
(b) Nutrient conservation is increased during succession
(c) Energy transfered from sun to producer is 1 to 5%
(d) Vegetation of biome is decided by climate.
Which is/are correct ?
(1) only a
(2) a,b
(3) a,b,c
(4) a,b,c,d
49.
ÙãUè´
çÙÙ ·¤ÍÙæð´ ·¤æ ØæÙÂêßü·¤ ¥ØØÙ ·¤èçÁ° (a) Áèß SÌÚU ÂÚU ÂæçÚUçSÍçÌ·¤è ¥æßàØ·¤ M¤Â âð ç·ý¤Øæ×·¤ ÂæçÚUçSÍçÌ·¤è
ãUæðÌè ãñUÐ
(b) §U·¤æðçâSÅU× ÎëàØ Öêç× ·¤è â´ÚU¿Ùæ×·¤ §U·¤æ§üU ãñUÐ
(c) ÎëàØ Öêç× §U·¤æðçâSÅU× ·¤è â´ÚU¿Ùæ×·¤ §·¤æ§üU ãñUÐ
(d) Áèß SÌÚU ÂÚU §U·¤æðÜæðÁè ¥æßàØ·¤ M¤Â âð ¥æÙéßæ´çàæ·¤ §U·¤æðÜæðÁè
ãñUÐ
(1) c ÌÍæ d âãUè ãñU
(2) b ÌÍæ d âãUè ãñU
(3) c ÌÍæ d ¥âØ ãñU
(4) a ÌÍæ b âãUè ãñU
(a) â´Øæ ·ð¤ çÂÚUæ×èÇU ç·¤âè çßàæðá ÿæðæ ×ð´ ÃØçCUØæð´ ·¤è â´Øæ ·¤æð
ÎàææüÌð ãñUÐ
(b) ¥Ùé·ý¤×æ ·ð¤ ÎæñÚUæÙ Âæðá·¤ â´ÚUÿææ ÕÉ¸UÌæ ãñUÐ
(c) âêØü ·ð¤ ©UÂæÎ·¤ Ì·¤ ª¤Áæü SÍæÙæÌÚUæ 1 âð 5% Ì·¤ ãUæðÌæ ãñUÐ
(d) ÕæØæð× ·¤è ßÙSÂçÌ ·¤æ çÙææüÚUæ ßæÌæßÚUæ ·¤ÚUÌæ ãñUÐ
çÙÙ ×ð´ âð ·¤æñÙâæ âãUè ãñU ?
(1) ·ð¤ßÜ a (2) a,b
(3) a,b,c
(4) a,b,c,d
49.
Identify the gases A, B, C, D and point out the 'X' gas
responsible for ozone deplition (i) N2O
(ii) methane
(iii) Chlorofluoro carbon
(iv) Carbondioxide
A
©UÂÚUæðQ¤ »ñâæð´ A, B, C, D ·¤è ÂãU¿æÙ ·¤èçÁ° ÌÍæ ¥æðÁæðÙ ¥ÂæÅUÙ ·ð¤
çÜ° ©UæÚUÎæØè »ñâ 'X' ·¤æð ç¿çãUÌ ·¤èçÁØð (i) N2O
(ii) ×ñÍðÙ
(iii) ÜæðÚUæðËØé¥æðÚUæð ·¤æÕüÙ
(iv) ·¤æÕüÙÇUæ§U¥æòâæ§UÇU
B
C
D
X
A
(1) ii
i
iv
iii
iii
(2) iv
iii
ii
i
(3) ii
i
iii
(4) iv
ii
iii
/+1
B
C
D
X
(1) ii
i
iv
iii
iii
ii
(2) iv
iii
ii
i
ii
iv
iv
(3) ii
i
iii
iv
iv
i
iii
(4) iv
ii
iii
i
iii
10
Full Syllabus-IV
50. Identify the components labelled a, b, c and d in the diagram 50.
below from the list i to vi given along with-
æÅU·¤:
(i) â×âêæè
(iii) çmUÌèØ ª¤âæ§UÅU
(v) Öýêæ ÁèßÙ
âãUè æÅU·¤ ãñÚ-
Components:
(i) Mitosis
(ii) First meiotic division
(iii) Secondary oocyte
(iv) First polar body
(v) Fetal life
(vi) After birth
The correct components are -
(vi) Á× Âà¿æÌ÷
c
d
(1)
ii
i
v
vi
vi
(2)
iii
ii
v
vi
i
v
(3)
ii
iii
i
v
vi
v
(4)
iii
v
vi
v
c
d
(1)
ii
i
v
vi
(2)
iii
ii
v
(3)
ii
iii
(4)
iii
v
51. Read the statements and choose the incorrect options -
51.
(1) After implanatation the inner cell mass differentiates
into germinal layer
(2) Human male ejaculates about 200-300 million sperms
per coitus
(3) For fertility, at least 60% of ejaculated sperms must
have normal shape size
(4) Inseminated sperms receive nutrients from vas deferens
and epididymis
52. Cortical granules are made of ................ and 52.
form.................during fertilisation (1) Golgi body: Fertilisation cone
(2) Golgi body: Fertilisation membrane
(3) Mitochondria : Fertilisation membrane
(4) Mitochondria : Zona pellucida
·¤æð Ùè¿ð Îè »§Uü
(iv) ÂýÍ× ÂæðÜÚU ·¤æØ
b
b
d
(ii) ÂýÍ× ¥hüUâêæè çßÖæÁÙ
a
a
/+1
çÎØð »Øð ç¿æ ×ð´ ÎàææüØð »Øð æÅU·¤æð´ a, b, c ÌÍæ
âæÚUæè ×ð´ âð i âð vi ç×ÜæÙ ·¤èçÁ° -
·¤ÍÙæð´ ·¤æð ÂçÉUØð ÌÍæ ¥âØ çß·¤ËÂ ·¤æ ¿ØÙ ·¤èçÁ°(1) ÚUæðÂæ ·ð¤ ÕæÎ ¥ÌÑ ·¤æðçàæ·¤èØ â×êãU ÁÙçÙ·¤ SÌÚUæð´ ×ð´ çßÖæçÁÌ
ãUæð ÁæÌæ ãñU
(2) ÙÚU ×ÙécØ °·¤ âãUßæâ ·ð¤ ÎæñÚUæÙ Ü»Ö» 200-300 million
àæé·ý¤ææé S¹çÜÌ ·¤ÚUÌæ ãñU
(3) ÁÙÙ ÿæ×Ìæ ·ð¤ çÜ° S¹çÜÌ àæé·ý¤ææé¥æð´ ×ð´ ·¤× âð ·¤× 60% ·¤è
¥æ·¤æÚU, ¥æ·ë¤çÌ âæ×æØ ãUæðÙè ¿æçãU°
(4) ¥ÌÑâðç¿Ì àæé·ý¤ææé àæé·ý¤ßæçãUçÙØæð´ ÌÍæ ¥çæßëáæ âð Âæðá·¤ ÂÎæÍü
»ýãUæ ·¤ÚUÌð ãñÚ
·¤æðçÅUü·¤Ü ·¤çæ·¤æ°´ ................ âð çÙç×üÌ ãUæðÌè ãñU ÌÍæ çÙáð¿Ù ·ð¤
ÎæñÚUæÙ.................·¤æ çÙ×æüæ ·¤ÚUÌè ãñU(1) »æòËÁè·¤æØ : çÙáð¿Ù àæ´·é¤
(2) »æòËÁè·¤æØ : çÙáð¿Ù çÛæËÜè
(3) ×æ§UÅUæð·¤æòçÇU™Øæ : çÙáð¿Ù çÛæËÜè
(4) ×æ§UÅUæð·¤æòçÇU™Øæ: ÁæðÙæ ÂðÜéçâÇUæ
11
Full Syllabus-IV
53. Correct statement is -
53.
(1) Coelentrates have bilateral symmetry
(2) Molluscans have biradial symmetry
(3) Ctenophora have radial symmetry
(4) Aschelminthes have radial symmetry
54. (i) Auxins also induce parthenocarpy in tomato
54.
(ii) Cytokinens help to produce new leaves
(iii) Ethephon hastens fruit ripening in tomatoes
(iv) Cytokinins help to overcome the apical dominant
(1) (i) and (ii) are correct only
(2) (iii) and (iv) are correct only
(3) (i) and (iii) are correct only
(4) (i), (ii), (iii) and (iv) are correct
55. Find out the incorrect statement the following -
55.
(1) Pyrenoids contains proteins besides starch.
(2) Asexual reproduction in brown algae by biflagellated
zoospores.
(3) The red algae usually reproduce vegetatively by budding.
(4) Chlamydomonas is a unicellular motile algae.
56. Identify the correct match from the column I, II, and III Column I
Column II
56.
âØ ·¤ÍÙ ãñU(1) çâÜðÅþðUÅUæ ×ð´ çmUÂæàßü â×ç×Ìè ãUæðÌè ãñU
(2) ×æðÜS·¤æ ×ð´ çm¥ÚUèØ â×ç×Ìè ãUæðÌè ãñU
(3) ÅUèÙæðÈ¤æðÚUæ ×ð´ ¥ÚèØ â×ç×Ìè ãUæðÌè ãñU
(4) °S·ð¤ãðUçË×çÍÁ ×ð´ ¥ÚUèØ â×ç×Ìè ãUæðÌè ãñU
(i) ¥æòçââ ÅU×æÅUÚU ×ð´ ¥çÙáð·¤È¤ÜÙ ·¤æð ÂýðçÚUÌ ·¤ÚUÌæ ãñUÐ
(ii) âæ§UÅUæð·¤æ§UçÙÙ Ù§üU ÂæèØæð´ ·ð¤ çÙ×æüæ ×ð´ ×ÎÎ ·¤ÚÌæ ãñUÐ
(iii) °çÍÈ¤æòÙ ÅU×æÅUÚU ·ð¤ È¤Ü ·ð¤ È¤Üæð´ ·¤æð Â·¤æÙð ·¤è »çÌ ·¤æð ÕÉ¸UæÌæ ãñUÐ
(iv) âæ§UÅUæð·¤æ§UçÙÙ çàæ¹æ»ý ÂýlæØÌæ âð ÀéUÅU·¤æÚUæ çÎÜßæÌæ ãñUÐ
(1) ·ð¤ßÜ (i) ÌÍæ (ii) âãUè ãñU
(2) ·ð¤ßÜ (iii) ÌÍæ (iv) âãUè ãñU
(3) ·ð¤ßÜ (i) ÌÍæ (iii) âãUè ãñU
(4) (i), (ii), (iii) ÌÍæ (iv) âãUè ãñU
çÙÙçÜç¹Ì ×ð´ âð »ÜÌ ·¤ÍÙ ·¤æð ÀUæ´çÅUØð (1) Âæ§ÚUèÙæò§UÇU SÅUæ¿ü ·ð¤ ¥Üæßæ ÂýæðÅUèÙ ÚU¹Ìð ãñÚÐ
(2) ÖêÚÔU àæñßæÜ ×ð´ ¥Üñ´ç»·¤ ÁÙÙ çmU·¤àææçÖç·¤Ø ¿Ü ÕèÁææé âð ãUæðÌæ
ãñUÐ
(3) ÜæÜ àæñßæÜ ÂýæØÑ ·¤æçØ·¤ ÁÙÙ ×é·é¤ÜÙ âð ·¤ÚUÌè ãñUÐ
(4) Üð×æ§UÇUæð×æðÙæâ °·¤·¤æðçàæ·¤èØ ¿Ü àæñßæÜ ãñUÐ
SÌÖ I, II, ÌÍæ III ·¤è âãUè ÂãU¿æÙ ·¤èçÁØð -
(3)
SÌÖ-I
ÜæðÚUæðÈ¤æ§U°âè
çÈ¤ØæðÈ¤æ§U°âè
°S·¤æð×æ§UçâÅUèÁ
(4)
ÕðâèçÇUØæð×æ§UçâÅUèÁ
Column III
(1) Chlorophyceae (a) Conidia
(i)
Fucus
(1)
(2) Pheophyceae
(b) Pyrenoid
(ii)
Somatogamy
(2)
(3) Ascomycetes
(c) Calmp
(iii) Isokont
(a)
(b)
(c)
conection
(4) Basidiomycetes (d) Fucoxanthin (iv) Penicillium
(d)
SÌÖ-II
·¤æðÙèçÇUØæ
Âæ§UÚUèÙæò§UÇU
ÜðÂ
·¤ÙðàæÙ
Øé·¤æðÁð́çÍÙ
Options :
çß·¤ËÂ :
(1) 3-b-ii, 4-c-i, 2-a-iii, 1-d-iv
(1) 3-b-ii, 4-c-i, 2-a-iii, 1-d-iv
(2) 3-d-i, 3-b-iii, 4-c-iv, 1-a-ii
(2) 3-d-i, 3-b-iii, 4-c-iv, 1-a-ii
(3) 1-b-iii, 2-d-i, 3-a-iv, 4-c-ii
(3) 1-b-iii, 2-d-i, 3-a-iv, 4-c-ii
(4) 1-a-ii, 2-c-iii, 3-b-iv, 4-b-i
(4) 1-a-ii, 2-c-iii, 3-b-iv, 4-b-i
57. What is a tonoplast -
57.
(1) Outer membrane of mitochondria
(2) Inner membrane of chloroplast
(3) Membrane boundary of the vacuole of plant cells
(4) Cell membrane of plant cell
/+1
(i)
(ii)
SÌÖ-III
Øé·¤â
âæð×ðÅUæð»ð×è
(iii) Isokont
(iv)
ÂðÙèçâçÜØ×
ÅUæðÙæðÜæSÅU Øæ ãñU ?
(1) ×æ§UÅUæð·¤æòçÇþUØæ ·¤è ÕæãUÚUè çÛæè
(2) ÜæðÚUæðÜæSÅU ·¤è ÖèÌÚUè çÛæè
(3) ÂæÎÂ ·¤æðçàæ·¤æ¥æð´ ·¤è ÚUâææÙè ·¤è çÛæè
(4) ÂæÎÂ ·¤æðçàæ·¤æ ·¤è ·¤æðçàæ·¤æ çÛæè
12
Full Syllabus-IV
58.
58.
çÎØð »Øð ç¿æ ·ð¤ çÜ° âãUè Üÿææ ·¤è ÂãU¿æÙ ·¤èçÁ°(a) ØãU ¿æÚU ÁæðÇ¸ð´ Üæð× Áæð ç·¤ ¥æòÂÚU·ê¤Ü× âð ÉU·ð¤ ãéUØð ØéQ¤ ãUæðÌð ãñU
Identify the correct characters for given animal (a) They have four pairs of gills without covered by an
operculum.
(b) §Uâ×ð´
(b) Notochord persistent throughout life
(c) Due to absence of air bladder they have to swim
constantly to avoid sinking
(d) They are mostly oviparous and development is direct.
(1) a and d
(2) a and c
(3) a, c and d
(4) b and c
59. Unlike Bryophytes & Pteridophytes in ......(A).... the male 59.
& the female gametophyte do not have .......(B)..............
ÁèßÙÂØüÌ ÙæðÅUæð·¤æðÇUü ÂæØè ÁæÌè ãñU
(c) ßæØé ·¤æðàææð´ ·¤è ¥ÙéÂçSÍçÌ ·ð¤ ·¤æÚUæ ØãU ÇêÕÙð âð Õ¿Ùð ·ð¤ çÜ°
Ü»æÌæÚU ÌñÚUÌè ãñUÐ
(d) Øð ×éØÌÑ ¥ÇUÁ ÌÍæ §Uâ×ð´ ÂýØÿæ ÂçÚUßæüÙ ãUæðÌæ ãñU
(1) a ÌÍæ d
(2) a ÌÍæ c
(3) a,c ÌÍæ d
(4) b ÌÍæ c
......(A).... ×ð´ ÕýæØæðÈ¤æ§UÅUæ °ß´ ÅðUçÚUÇUæðÈ¤æ§UÅU ·¤è ÌÚUãU ÙÚU ÌÍæ ×æÎæ
Øé×·¤æðÎ÷çÖÎ .......(B)......... ÙãUè´ ãUæðÌæ ãñUÐ
existance
60.
©UÂÚæðQ¤ ·¤ÍÙ ×ð´ A ß B ·¤æð ÖçÚU° (1) A : °çÁØæðSÂ×ü;
B : çÙÖüÚU
(2) A : çÁÙæðSÂ×ü;
B : çÙÖüÚU
(3) A : àæñßæÜ;
B : ×éQ¤ Áèßè
(4) A : çÁÙæðSÂ×ü;
B : SßÌæ ×éQ¤ Áèßè
çÙÙ âæÚUæè ×ð´ âãUè ç×ÜæÙ ·¤æð ÂãU¿æçÙØðÐ
(i)
SÌÖ -I
Âý·¤æàæ-àßâÙ
In above statement fill A & B (1) A : Angiosperm;
B : Dependent
(2) A : Gymnosperm;
B : Dependent
(3) A : Algae;
B : Free Living
(4) A : Gymnosperm;
B : Independent free living
60. Find out the correct match in following tabel.
Column-I
(i) Photorespiration
Column-II
Column-III
Glycolate pathway
two organelle
SÌÖ-II
Üæ§U·¤æðÜðÅU ÂæÍßð
SÌÖ-III
Îæð çÛæè ØéQ¤
Îæð ·¤æðçàæ·¤æ´»
(ii) C4 -ÂæÎÂ
·ý¤æÁ àææÚUèçÚU·¤è
(iii) C3 -ÂæÎÂ
·ý¤æÁ àææÚUèçÚU·¤è
¥ÙéÂçSÍÌ
ÂýæÍç×·¤ CO2
çSÍÚUè·¤ÚUæ
RubisCo mUæÚUæ
CO2 ·¤æ
çSÍÚUè·¤ÚUæ ·ð¤ßÜ
RubisCo mUæÚUæ
with double
membrane
(ii) C4-plants
Kranz Anatomy
Primary CO2
fixation by
RubisCo
(iii) C3-plants
Kranz Anatomy
CO2 fixation
absent
only by
RubisCo
(1) (i) only
(2) (i), (iii)
(3) (ii) only
(4) (ii), (iii)
/+1
(1) ·ð¤ßÜ (i)
(3) ·ð¤ßÜ (ii)
(2) (i), (iii)
(4) (ii), (iii)
13
Full Syllabus-IV
61. Which one of the following options gives the correct 61.
categorisation of substages of prophase-I?
A
B
ç·¤â °·¤ çß·¤ËÂ ×ð´ ÂêßæüßSææ-I ·¤è ©UÂ¥ßSÍæ¥æð´ ·¤è âãUè æðæè Îè
»§üU ãñU ?
C
A
B
C
Diplotene
Âð·¤æ§UçÅUÙ
·¤æØð×ðÅUæ
çÙ×æüæ
çÚU·¤æòçÕÙðÁ
âç·ý¤ØÌæ
©UÂæ´ÌèÖßÙ
·ý¤æòçâ´» ¥æðßÚU
çÇUÜæðçÅUÙ
©UÂæ´ÌèÖßÙ
Terminalisation
(1)
Áæ§U»æðçÅÙ
ÁèÙ-çßçÙ×Ø
Recombinase
Repulsion in
(2)
Øé×Ù
action
chromosome starts
(3) Tetrad visible
Terminalisation
Gene-Exchange
(3)
¿Ìéc·¤ ÎëçCU»Ì
(4) 0.3% DNA
Crossing over
Nucleolus
(4) 0.3% DNA
Zygotene
Pachytene
(1) Gene-Exchange Chiasmata
formation
(2) Synapsis
replication
ÂýçÌ·ë¤çÌ·¤ÚUæ
disappear
62. Consider the following statements (a-d) and select the 62.
option which includes all the correct ones only.
(a) In Aerobic prokaryotes the TCA-cycle takes place in
cytosol.
(b) Auxin was first isolated from human urine.
unicellular eukaryotes.
(d) Aerobic respiration occurs only in eukaryotes.
Option (1) Statement b, c and d
(2) Statement a, b and c
(3) Statement c, d
(4) Statement a, c and d
63. Specialised cells called as flame cells help in osmoregulation 63.
and excretion in (2) Ctenophore
(3) Platyhelminthes
(4) Aschelminthes
64. Of the following statements incorrect one is (1) The infected macrophase cell can survive while viruses
are beings replicated and released.
(2) The HIV/AIDS infected persons are to be isolated from
family and society.
(3) There is always a time-lag between the infection and
appearance of AIDS symptoms.
(4) HIV/AIDS is not spread by mere touch or physical contact
/+1
çÙÙçÜç¹Ì ·¤ÍÙæð´ (a-d) ÂÚU çß¿æÚU ·¤èçÁ° ¥æñÚU ·ð¤ßÜ âÖè âãUè
·¤ÍÙæð´ ßæÜæ °·¤ çß·¤ËÂ ¿éçÙØðÐ
(a) ßæØßèØ Âýæð·ð¤çÚUØæðÅ÷Uâ ×ð´ TCA-¿·ý¤ âæØÅUæðâæðÜ ×ð´ ãUæðÌæ ãñUÐ
(b) ¥æòçâÙ
(c) Fermentation takes place by many prokaryotes and
(1) Coelentrates
»éæâêææð´ ×ð´
ÂýçÌ·¤áüæ ÂýæÚÚÖ
ÁèÙ-çßçÙ×Ø
·ð¤çÎý·¤æçßÜé#
64.
âßüÂýÍ× ×æÙß ×êæ âð ÂëÍ·¤ ç·¤Øæ »Øæ ÍæÐ
(c) ç·¤ßÙ ·¤§üU Âýæð·ð¤çÚUØæðÅ÷Uâ ÌÍæ °·¤ ·¤æðçàæ·¤èØ Øê·ð¤çÚUØæðÅU÷â mUæÚUæ
ãUæðÌæ ãñUÐ
(d) ßæØßèØ àßâÙ ·ð¤ßÜ Øê·ð¤çÚUØæðÅ÷Uâ ×ð´ ÂæØæ ÁæÌæ ãñUÐ
çß·¤ËÂ (1) ·¤ÍÙ b, c ÌÍæ d
(2) ·¤ÍÙ a, b ÌÍæ c
(3) ·¤ÍÙ c, d
(4) ·¤ÍÙ a, c ÌÍæ d
çßàæðá Âý·¤æÚU ·¤è ·¤æðçàæ·¤æ°´, ßæÜæ ·¤æðçàæ·¤æ°´ ÂÚUæâÚUæ çÙØ´ææ ÌÍæ
©UâÁüÙ ×ð´ âãUæØÌæ ·¤ÚUÌè ãñU, ÂæØè ÁæÌè ãñU(1) çâÜðÅþðUÅU ×ð´
(2) ÅUèÙæðÈ¤æðÚU ×ð´
(2) ÜðçÅUãðUçË×çÍÁ ×ð´
(4) °S·ð¤ãðUçË×çÍÁ ×ð´
çÎØð »Øð ·¤ÍÙæð´ ×ð´ âð °·¤ »ÜÌ ·¤ÍÙ ãñU (1) â´·ý¤ç×Ì ßëãUÌ÷ Öÿæ·¤ææé ÁèçßÌ ÚUãU â·¤Ìè ãñU ÁÕç·¤ çßáææé¥æð´
·¤è ÂýçÌ·ë¤çÌØæ´ ÕæÌè ãñ ¥æñÚU ×æðç¿Ì ãUæðÌè ãñUÐ
(2) HIV/AIDS â´·ý¤ç×Ì ÃØçQ¤ ·¤æð ÂçÚUßæÚU âð Øæ â×æÁ âð ¥Ü»ÍÜ» ·¤ÚU ÎðÙæ ¿æçãU°Ð
(3) â´·ý¤×æ ãUæðÙð ¥æñÚU AIDS ·ð¤ Üÿææ Âý·¤ÅU ãUæðÙð ·ð¤ Õè¿ ãU×ðàææ
¥ÌÚUæÜ ãUæðÌæ ãñUÐ
(4) HIV/AIDS ·ð¤ßÜ ÀéUÙð ×æÌë Øæ àæÚUèÚ ·ð¤ âÂ·ü¤ ×ð´ ¥æÙð âð Ùãè´
Èñ¤ÜÌæ ãñUÐ
14
Full Syllabus-IV
65. A benign tumor is more likely to become malignant when 65.
(1) The tumour cells no longer respond to growth factor
signals.
(2) The rate of cell division slows down.
(3) It reaches a certain size.
(4) Several tumour suppressor genes are inactivated by
âéÎ× ¥ÕéÎüU ·¤æ ÂçÚUßÌüÙ ÎéÎü× ¥ÕêÎü ×ð´ ãUæð â·¤Ìæ ãñ,U ÁÕç·¤ (1) ¥ÕéÎü ·¤æðçàæ·¤æ ßëçhU ·¤æÚU·¤ â´·ð¤Ìæð´ ·ð¤ çßM¤hU ·¤æð§üU ¥Ùéç·ý¤Øæ ÙãUè´
·¤ÚÔU
(2) ·¤æðçàæ·¤æ çßÖæÁÙ ·¤è ÎÚU æÅU ÁæØð
(3) ØãU °·¤ çÙçà¿Ì ¥æ·¤æÚU ßæÜè ãUæð ÁæØð
(4) ¥Ùð·¤ ¥ÕéÎü â´Î×·¤ ÁèÙæð´ ·¤æð ©UÂçÚUßÌüÙæð´ mUæÚUæ çÙçc·ý¤Ø ãUæðÙð âð
mutations.
66. In radiotherapy tumor cells are irradiated, these cells are 66.
more easily damaged by radiation than normal cells
because they (1) have proto oncogenes in them
(2) are undergoing rapid division
(3) are different in structure
(4) have oncogenes in them
67. How many of the statements are true for vernalisation?
67.
(a) It prevents precocious reproductive development late
in the growing season.
(b) It affects quantity & quality of flowering.
(c) Spring varieties of wheat require vernalisation.
(d) Artificial vernalisation shortens the life span in biennial
plants.
(e) âÖè Âæñææð´ ×ð´ ÂécÂÙ ·ð¤ çÜ° ßâ´Ìè·¤ÚUæ ·¤è ¥æßàØ·¤Ìæ ãæðÌè ãñUÐ
(e) Vernalisation is required by all plants to initiate flowering.
(1) Two
(2) Three
(3) One
(4) Four
(1) Îæð
(3) °·¤
68. CO2 â´ÌéÜÙ·¤æÚUè
68. CO2 compensation point is
(1) 360 ppm for C4 plants
(2) The point at which light intensity is the limiting factor
(3) Observed in open atmosphere during morning and
evening time
(4) Lower for C4 plants and higher for C3 plants
69. In transamination process when glutamic acid is the donor 69.
of amino group and pyruvic acid is the acceptor then (1) asparatic acid is formed
(2) alanine is formed
(3) asparagine is formed
(4) glutamine is formed
70. Drugs which are used as medicine to help patient cope 70.
with mental illness like derpession and insomnia (1) Barbiturates
(2) Diacetylmorphine
(3) Antihistamine
(4) Antibiotics
/+1
ÚÔUçÇUØæðÍñÚÔUÂè ×ð´ ¥ÕéÎü ·¤æðçàæ·¤æ¥æð´ ÂÚU çßç·¤ÚUæð´ ÇUæÜè ÁæÌè ãñU, ØãU
·¤æðçàæ·¤æ°´ àæÚUèÚU ·¤è âæ×æØ ·¤æðçàæ·¤æ¥æð´ ·¤è ÌéÜÙæ ×ð´ ¥æâæÙè âð ÙCU
ãUæð ÁæÌè ãñÚ, Øæð´ç·¤ (1) §UUÙ×ð´ ÂýæðÅUæð ¥æð´·¤æðÁèÙ Âæ° ÁæÌð ãñU
(2) Øð Ìèßý çßÖæÁÙ ·¤ÚUÌè ãñÚ
(3) Øð â´ÚU¿Ùæ ×ð´ çÖóæ ãUæðÌè ãñÚ
(4) §UUÙ×ð´ ¥æð´·¤æðÁèÙ Âæ° ÁæÌð ãñU´
ßâ´Ìè·¤ÚUæ ·ð¤ çÜ° çÙÙ ×ð´ âð ç·¤ÌÙð ·¤ÍÙ âãUè ãñU ?
(a) ØãU ¥·¤æçÜ·¤ ÂýÁÙÙ ÂçÚUßæüÙ ·¤æð ßëçhU ·ð¤ ×æñâ× ×ð´ ÌÕ Ì·¤
ÚUæð·¤Ìæ ãñU ÁÕ Ì·¤ Âæñæð ÂçÚUÂß Ù ãUæð Áæ°´Ð
(b) ØãU ÂécÂÙ ·¤æð »éææ×·¤ °ß´ ×æææ×·¤ ÌæñÚU ÂÚU ÂýÖæçßÌ ·¤ÚUÌæ ãñUÐ
(c) »ðãê¡U ·¤è ßâ´Ì ç·¤S×æð´ ×ð´ ßâ´Ìè·¤ÚUæ ·¤è ¥æßàØ·¤Ìæ ãUæðÌè ãñUÐ
(d) ·ë¤çæ× ßâ´Ìè·¤ÚUæ çmUßáèü Âæñææð´ ×ð´ ÁèßÙ ·¤æÜ ·¤æð ·¤× ·¤ÚUÌæ ãñUÐ
(2) ÌèÙ
(4) ¿æÚU
çÕÎé ãñU (1) Áæð ç·¤ C4 ÂæÎÂæð´ ×ð´ 360 ppm ãUæðÌæ ãñUÐ
(2) §Uâ ÂÚU Âý·¤æàæ ·¤è ÌèßýÌæ °·¤ çÙØæ×·¤ ·¤æÚU·¤ ãUæðÌè ãñUÐ
(3) Áæðç·¤ ¹éÜð ßæØé×´ÇUÜ ×ð´ âéÕãU °ß´ àææ× ·ð¤ â×Ø Îð¹æ Áæ â·¤Ìæ
ãñUÐ
(4) Áæð ç·¤ C4 ÂæÎÂ ·ð¤ çÜ° ·¤× ß C3 ÂæÎÂæð´ ·ð¤ çÜ° ¥çæ·¤ ãUæðÌæ ãñUÐ
ÂæÚU-°×èÙÙ Âýç·ý¤Øæ ×ð´ ÁÕ ÜéÅUæç×·¤ ¥Ü ¥×èÙæð â×êãU ·¤æ ÎæÌæ
°ß´ ÂæØM¤çß·¤ ¥Ü §Uâ·¤æ »ýæãUè ãUæð Ìæð (1) °SÂæÚUçÅU·¤ ¥Ü ·¤æ çÙ×æüæ ãUæðÌæ ãñU
(2) °çÜÙèÙ ·¤æ çÙ×æüæ ãUæðÌæ ãñU
(3) °SÂæÚUÁèÙ ·¤æ çÙ×æüæ ãUæðÌæ ãñU
(4) ÜéÅUæ×èÙ ·¤æ çÙ×æüæ ãUæðÌæ ãñU
¥æñáçæ Áæð ¥ßâæÎ ¥æñÚU ¥çÙÎýæ Áñâð ×æÙçâ·¤ ÃØæçæ âð »ýSÌ ÚUæðç»Øæð´
·¤è âãUæØÌæ ·ð¤ çÜ° âæ×æØÌÑ ÂýØéQ¤ Üè ÁæÌè ãñU, ØãU ãñU (1) ÕæÕèüÅKéÚÔUÅ÷Uâ
(2) ÇUæ§U°çâÅUæ§UÜ×æòçÈü¤Ù
(3) °çÅUçãUSÅUæç×Ù
(4) °ÅUèÕæØæòçÅU·¤
15
Full Syllabus-IV
71. In the given diagram of chloroplast identify activities releated 71.
to positions marked as A, B, C & D -
A
(1) Light reaction
B
C
D
Only ATP
Dark
Sugar
synthesis
reaction
storage
Only ATP
Sugar
Sugar
synthesis
synthesis
storage
Sugar
RuBisCO
Protein
synthesis
synthesis
synthesis
cyclic and
Dark
Protein
photophos-
non cyclic
reaction
synthesis
phorylation
photophos-
only
phorylation
(2) Dark reaction
(3) Cyclic
photophos-
A
(1)
(2)
(3)
phorylation
(4) Cyclic
ãUçÚUÌÜß·¤ ·ð¤ çÎ° »° ç¿æ ×ð´ A, B, C ß D âð Îàææü° Öæ»æð´ ·ð¤ ·¤æØü
ÂãU¿æÙð´ -
(4)
72. The water potential and osmotic pressure of pure water 72.
B
C
Âý·¤æàæ ¥çÖç·ý¤Øæ ·ð¤ßÜ ATP
â´àÜðáæ
¥´æ·¤æÚU ¥çÖç·ý¤Øæ ·ð¤ßÜ ATP
â´àÜðáæ
¿·ý¤èØ
àæ·ü¤ÚUæ
È¤æðÅUæ-ð
â´àÜðáæ
È¤æòSÈ¤æðçÚUÜàð æÙ
·ð¤ßÜ
¿·ý¤èØ °ß´
¿·ý¤èØ
¥¿·ý¤èØ
È¤æðÅUæ-ð
È¤æðÅUæ-ð
¥´æ·¤æÚU
¥çÖç·ý¤Øæ
àæ·ü¤ÚUæ
â´àÜðáæ
D
â´àÜðáæ
àæ·ü¤ÚUæ
â´¿ØÙ
àæ·ü¤ÚUæ
â´¿ØÙ
ÂýæðÅUèÙ
â´àÜðáæ
¥´æ·¤æÚU
¥çÖç·ý¤Øæ
ÂýæðÅUèÙ
â´àÜðáæ
RuBisCO
àæéhU ÁÜ ·¤æ ÁÜ çßÖß ÌÍæ ÂÚUæâÚUæ ÎæÕ ãñU -
are (1) 100 and Zero
(2) Zero and Zero
(3) 100 and 200
(4) Zero and 100
73. In a HIV infected person there is a group of symptoms 73.
which are due to (1) Only viral infections
(2) Bacterial and Viral infections
(3) Viral, Bacterial and Fungal infections
(4) Viral, Bacterial, Fungal and parasitic infections
74. The volume of air involved in breathing movements can be 74.
estimated by using a instrument which helps in clinical assessment of pulmonary functions (1) Spectrometer
(2) Spirometer
(3) Stethoscope
(4) Blood pressure instrument
75. Brunner's glands are located in 75.
(1) Duodenal mucosa
(2) Duodenal submucosa
(3) Gastric mucosa
(4) Gastric submucosa
/+1
(1) 100 ÌÍæ àæêØ
ÌÍæ àæêØ
(3) 100 ÌÍæ 200
(4) àæêØ ÌÍæ 100
°·¤ HIV â´·ý¤ç×Ì ÃØçQ¤ ×ð´ Üÿæææð´ ·¤æ â×êãU ãUæðÌæ ãñU ØãU Üÿææ ãUæðÌð
ãñU (1) ·ð¤ßÜ çßáææé ·ð¤ â´·ý¤×æ âð
(2) Áèßææé ÌÍæ çßáææé ·ð¤ â´·ý¤×æ âð
(3) çßáææé, Áèßææé ÌÍæ ·¤ß·¤ ·ð¤ â´·ý¤×æ âð
(4) çßáææé, Áèßææé, ·¤ß·¤ ÌÍæ ÂÚUÁèßèØæð´ ·ð¤ â´·ý¤×æ âð
àßâÙ »çÌçßçæØæð´ ×ð´ âç×çÜÌ ßæØé ·¤æ ¥æ´·¤ÜÙ °·¤ Ø´æ ·¤è
âãUæØÌæ âð ç·¤Øæ Áæ â·¤Ìæ ãñU Áæð Èé¤Èé¤âè ·¤æØü·¤ÜæÂæð´ ·¤æ ÙñÎæçÙ·¤
×éËØæ´·¤Ù ·¤ÚUÙð ×ð´ âãUæØ·¤ ãUæðÌæ ãñU(1) SÂðÅþUæð×èÅUÚU
(2) SÂæ§UÚUæð×èÅUÚU
(3) SÅðUÍæðS·¤æðÂ
(4) ÚUÌ ÎæÕ ×æÂè Ø´æ
ÕýêÙÚU ·¤è »ý´çÍØæ´ ÂæØè ÁæÌè ãñU (1) »ýãUæè ·ð¤ Øê·¤æðâæ Öæ» ×ð´
(2) »ýãUæè ·ð¤ âÕØê·¤æðâæ Öæ» ×ð´
(3) ¥æ×æàæØ ·ð¤ Øê·¤æðâæ Öæ» ×ð´
(4) ¥æ×æàæØ ·ð¤ âÕØê·¤æðâæ Öæ» ×ð´
(2) àæêØ
16
Full Syllabus-IV
76. Given below are four statements (a-d) regarding human 76.
blood circulatory system :
(a) Arteries are thick-walled and have narrow lumen as
compared to veins.
(b) Cornea has rod and cone cells.
(c) Persons with blood group AB can donate blood to any
person with any blood group under ABO system.
(d) Calcium ions play a very important role in blood clotting
Which of the above statements are incorrect?
(1) (a) and (b)
(2) (b) and (c)
(3) (c) and (d)
(4) (a) and (d)
77. A person consume potato, digestion of its ingradients occurs 77.
as (1) Starch by amylase in stomach
(2) Starch by lipase in small intestine
(3) Nuclec acids by nucleases of pancrease in small intestine
(4) Nucleotides by nucleotidase of pancrease
78. Although the aerobic process of respiration takes place only 78.
in the presence of oxygen, the role of oxygen is limited to
the ____A____ of the process. yet, the presence of oxygen
is vital, since it drives the whole process by ____B___ from
Ùè¿ð çÎØð »Øð ·¤ÍÙ (a-d) çÎØð Áæ ÚUãðU ãñU´, çÁÙ·¤æ â´Õ´æ ×æÙß M¤çæÚU
ÂçÚUâ´¿ÚUæ Ì´æ âð ãñU(a) çàæÚUæ¥æð´ ·¤è ÌéÜÙæ ×ð´ æ×çÙØæ´ ¥çæ·¤ ×æðÅUè ÎèßæÚU ßæÜè ãUæðÌè ãñÚ
°ß´ ©UÙ·¤è ¥ß·¤æçàæ·¤æ â´·¤èæü ãUæðÌè ãñU
(b) ·¤æòçÙüØæ ×ð´ àæÜæ·¤æ ÌÍæ àæ´·é¤ ·¤æðçàæ·¤æØð´ ÂæØè ÁæÌè ãñUÐ
(c) AB ÚUÌ â×êãU ßæÜð ÃØçÌ ABO Ì´æ ·ð¤ ¥´Ì»üÌ ç·¤âè Öè ÃØçÌ
·¤æð ÚUÌÎæÙ Îð â·¤Ìð ãñÚ
(d) ÚUÌ-S·´¤ÎÙ ·¤è Âýç·ý¤Øæ ×ð́ ·ñ¤çËàæØ× ¥æØÙæð́ ·¤è ¥ØÌ ×ãUßÂêæü
Öêç×·¤æ ãUæðÌè ãñUÐ
ª¤ÂÚU çÎØð »Øð ·¤ÍÙæð´ ×ð´ð çÙÙ ×ð´ âð ·¤æñÙ âð ·¤ÍÙ ¥âØ ãñU (1) (a) ÌÍæ (b)
(2) (b) ÌÍæ (c)
(3) (c) ÌÍæ (d)
(4) (a) ÌÍæ (d)
°·¤ ÃØçÌ ¥æÜê ·¤æ âðßÙ ·¤ÚUÌæ ãñU, ¥æÜê ·ð¤ ¥ßØßæð´ ·¤æ Âæ¿Ù çÙÙ
Âý·¤æÚU âð ãUæðÌæ ãñU (1) SÅUæ¿ü ·¤æ Âæ¿Ù ¥×æ§UÜðÁ mUæÚUæ ¥æ×æàæØ ×ð´
(2) SÅUæ¿ü ·¤æ Âæ¿Ù Üæ§UÂðÁ mUæÚUæ ÀUæðÅUè ¥æ´æ ×ð´
(3) ØêçÜ ¥Üæð´ ·¤æ ¥ÙæàæØ ·ð¤ ØêçÜ°ðÁðÁ mUæÚUæ ÀUæðÅUè ¥æ´æ ×ð´
(4) ØêçËØæðÅUæ§UÇU ·¤æ ¥ÙæàæØ ·ð¤ ØêçÜØæðÅUæ§UÇðUÁ mUæÚUæ
àßâÙ ·¤è ¥æòâèÂýç·ý¤Øæ ¥æòâèÁÙ ·¤è ©UÂçSÍçÌ ×ð´ ãUè âÂóæ ãUæðÌè
ãñUÐ Âýç·ý¤Øæ ·ð¤ ____A____ ×ð´ ¥æòâèÁÙ ·¤è Öêç×·¤æ âèç×Ì ãUæðÌè
ãñUÐ ØlçÂ ¥æòâèÁÙ ·¤è ©UÂçSÍçÌ ¥æßàØ·¤ ãñU, Øæð´ç·¤ ØãU ÂêÚÔU Ì´æ
âð ____B___ ·¤ÚU ÂêÚUè Âýç·ý¤Øæ ·¤æð â´¿æçÜÌ ·¤ÚUÌè ãñUÐ
the system
(1) A = ETS,
B = removing electron
(1) A = ETS,
B = §UÜðÅþUæòÙ ·¤æð ×éQ¤
(2) A = Krebs cycle,
B = removing hydrogen
(2) A = ·ýð¤â ¿·ý¤,
B = ãUæ§UÇUþæðÁÙ ·¤æð ×éQ¤
(3) A = terminal stage,
B = removing hydrogen
(3) A = ¥´çÌ× ¿ÚUæ,
B = ãUæ§UÇUþæðÁÙ ·¤æð ×éQ¤
(4) A = link reaction and
B = removing electron
(4) A = çÜ´·¤ ¥çÖç·ý¤Øæ °ß´
B = §UÜðÅþUæòÙ ·¤æð ×éQ¤
Krebs cycle,
79. Which of the following graph correctly represents the 79.
variation in value of RQ when initially respiratory substrate
was carbohydrate, then fats and after that proteins ?
·ýð¤â ¿·ý¤,
çÙÙ ×ð´ âð ·¤æñÙâæ ß·ý¤ RQ ·ð¤ ×æÙ ×ð´ ÕÎÜæß ·¤æð âãUè M¤Â âð ÎàææüÌæ
ãñU, ØçÎ àßâÙ ×ð´ ÂãUÜð ·¤æÕæðüãUæ§UÇþðUÅU ·¤æ, ©Uâ·¤ð ÕæÎ ßâæ ·¤æ ¥æñÚU
©Uâ·ð¤ ÕæÎ ÂýæðÅUèÙ ·¤æ ©UÂØæð» ãUæð ?
(1)
(2)
(1)
(2)
(3)
(4)
(3)
(4)
/+1
17
Full Syllabus-IV
80. Keeping in view the fluid mosaic model for the structural of 80.
cell membrane. How many of the following statements is
ÃØæÂ·¤ M¤Â ×ð´ Sßè·ë¤Ì ·¤æðçàæ·¤æ çÛæè ·¤è ÌÚUÜ ×æðÁð·¤ ×æòÇUÜ ·ð¤
¥ÙéâæÚU çÙÙ ×ð´ âð ç·¤ÌÙð ·¤ÍÙ âãUè ãñU -
correct (A) çÜçÂÇU
(A) The quasi-fluid nature of lipid enables lateral movement
of protein with in overall bilayer
(B) The fluid nature of the membrane is not important for
formation of inter cellular junction
(C) Integral proteins lie on the surface of membrane while
the peripheral proteins are buried in the membrane
(D) All eukaryotic cell membrane have 52 percent protein
and 40 percent lipid
81.
(1) Two
(2) One
(3) Four
(4) Three
Identify the given cell organelle with their respective 81.
·ð¤ ¥æüÌÚUÜèØ Âý·ë¤çÌ ·ð¤ ·¤æÚUæ çmUâÌãU ·ð¤ ÖèÌÚU ÂýæðÅUèÙ
Âæçàßü·¤ »çÌ ·¤ÚUÌæ ãñUÐ
(B) çÛæËÜè ·¤è ÌÚUÜèØ Âý·ë¤çÌ ¥´ÌÚU·¤æðçàæ·¤èØ â´ØæðÁ·¤ ·ð¤ çÙ×æüæ ·ð¤
çÜ° ¥æßàØ·¤ ÙãUè´ ãñUÐ
(C) ¥´»ÖêÌ ÂýæðÅUèÙ çÛæè ·¤è âÌãU ÂÚU ãUæðÌæ ãñU, ÁÕç·¤ ÂçÚUçæØ ÂýæðÅUèÙ
çÛæè ×ð´ æ´âð ãUæðÌð ãñUÐ
(D) âÖè Øê·ñ¤çÚUØæðçÅU·¤ ·¤æðçàæ·¤æ¥æð´ ×ð´ 52 ÂýçÌàæÌ ÂýæðÅUèÙ ÌÍæ 40
ÂýçÌàæÌ çÜçÂÇU ç×ÜÌæ ãñUÐ
(1) Îæð
(2) °·¤
(3) ¿æÚU
(4) ÌèÙ
Ùè¿ð çÎ° »° ·¤æðçàæ·¤æ´» ·¤æð ©Uâ·ð¤ ·¤æØü ·ð¤ âæÍ ÂãU¿æçÙ° -
function -
Cell organelles
Function
·¤æðçàæ·¤æ´»
»æòËÁè·¤æØ
(1) Golgibody
Site for synthesis of steroid hormone
(1)
(2) SER
Site for synthesis of lipid
(2) SER
(3) Golgi Apparatus
Site for post translation modification
(3)
(4) Peroxisome
Involved in photorespiration
(4)
82. Prophase is marked by the -
82.
(1) Complete disintegration of nuclear envelope
(2) Initiation of condensation of chromosomal material
(3) Completion of the assembly of mitotic spindle
(4) Alignment of the chromosome at equatorial plate
83. Choose the wrong combination -
83.
(1) Steroids
Testosterone and estradiol
(2) Iodothyronines
Pituitary hormones
(3) Amino-acid derivatives Epinephrine
(4) protein or polypeptide
/+1
Insulin and glucagon
»æòËÁè·¤æØ
ÂÚU¥æòâèâæð×
·¤æØü
SÅUèÚUæØÇUÜ ãUæò×æðüÙ ·ð¤ çÙ×æüæ ·¤æ Âý×é¹ SÍÜ
çÜçÂÇU çÙ×æüæ ·ð¤ ×éØ SÍÜ
ÂæðSÅU ÅþUæ´âÜðàæÙ M¤ÂæÌÚUæ ·¤æ SÍÜ
Âý·¤æàæ àßâÙ ×ð´ âç×çÜÌ
ÂêßæüßSææ ·¤è ÂãU¿æÙ ç·¤ââð ãUæðÌè ãñU (1) ·ð¤Îý·¤èØ ¥æßÚUæ ·ð¤ ÂêæüÌØæ çßÂæÅUÙ âð
(2) »éæâêæèØ ÂÎæÍü ·ð¤ â´æÙÙ ·¤æ ÂýæÚÚÖ
(3) â×âêæè Ì·éü¤ ·ð¤ Á×æßÇ¸ð ·¤è Âýç·ý¤Øæ ·¤æ ¥´Ì
(4) »éæâêææð´ ·¤æ ×ØæßSÍæ ÂçÛ·¤æ ·¤è ¥æðÚU ÁæÙæ
çÙæ ×ð´ âð »ÜÌ ç×ÜæÙ ãñ(1) SÅUèÚUæò§UÇU
ÅðUSÅUæðSÅðUÚUæðÙ ÌÍæ °SÅþUæÇUæØæðÜ
(2) ¥æØæðÇUæðÍæ§UÚUæðçÙÙ
ÂèØêá »ý´çÍ ãUæ×æðüÙ
(3) ¥×èÙæð-¥Üæð´ ·ð¤ ÃØéÂæ °ÂèÙðÈ¤ý èÙ
(4) ÂýæðÅUèÙ Øæ ÂæòÜèÂðÅUæ§UÇU
§UâéçÜÙ ÌÍæ Üê·¤æ»æòÙ
18
Full Syllabus-IV
84. When a neuron is not conducting any impulse, i.e., resting, 84.
the axonal membrane is comparatively (1) More permeable to potassium ions (K+) and nearly
impermeable to sodium ions (Na+)
(2) More permeable to sodium ions (Na+) and nearly
impermeable to potassium ions (K+)
(3) More permeable to Calcium ions (Ca2+) and nearly
impermeable to Potassium ions (K+)
(4) Less permeable to potassium ions (K+) and nearly
impermeable to sodium ions (Na+)
85. In some cereals such as rice and wheat, pollen grains lose 85.
viability within .......of their release (1) 30 seconds
(2) 30 mintues
(3) 30 hours
(4) 30 days
86. Fungi are known to form symbiotic associations with plants. 86.
The fungal symbiont in these associations absorbs
phosphorus from soil and passes it to the plant. Beside this
plant also have other benefits. Which one of the following
is not a benefit gained by plant showing such associations(1) Resistance to root-borne pathogens
(2) Tolerance to salinity
(3) Tolerance to drought
(4) Resistance from fungal pathogens
87. How many of the given below statements are correct with 87.
reference to the pitutary gland (i) The pituitary gland is located in a bony cavity called
sella tursica of sphenoid bone.
(ii) It is divided anatomically into an adenohypophysis and
a neurohypophysis.
(iii) Pars intermedia secretes only one hormone called
melanocyte stimulating hormone (MSH).
(iv) posterior pituitary, stores and releases two hormones
calledoxytocin and vasopressin.
(1) One
(2) Two
(3) Three
(4) All are correct
/+1
ÁÕ ·¤æð§üU ÙØêÚUæòÙ ¥æßð»æð́ ·¤æ â´¿ÚUæ ÙãUè´ ·¤ÚUÌð ãñ́U, Áñâð ç·¤ çßÚUæ×æßSÍæ
×ð´ Ì´çæ·¤æÿæ çÛæËÜè (1) ÌéÜÙæ×·¤ M¤Â âð ÂæðÅñUçàæØ× ¥æØÙ (K +) ·ð¤ çÜ° ¥çæ·¤ ÂæÚU»Ø
ÌÍæ âæðçÇUØ× ¥æØÙ (Na +) ·ð¤ ÂýçÌ Ü»Ö» ¥ÂæÚU»Ø ãUæðÌè ãñ
(2) ÌéÜÙæ×·¤ M¤Â âð âæðçÇUØ× ¥æØÙ (Na+) ·ð¤ çÜ° ¥çæ·¤ ÂæÚU»Ø
ÌÍæ ÂæðÅñUçàæØ× ¥æØÙ (K+) ·ð¤ ÂýçÌ Ü»Ö» ¥ÂæÚU»Ø ãUæðÌè ãñ
(3) ÌéÜÙæ×·¤ M¤Â âð ·ñ¤çËàæØ× ¥æØÙ (Ca2+) ·ð¤ çÜ° ¥çæ·¤ ÂæÚU»Ø
ÌÍæ ÂæðÅñUçàæØ× ¥æØÙ (K+) ·ð¤ ÂýçÌ Ü»Ö» ¥ÂæÚU»Ø ãUæðÌè ãñ
(4) ÌéÜÙæ×·¤ M¤Â âð ÂæðÅñUçàæØ× ¥æØÙ (K +) ·ð¤ çÜ° ·¤× ÂæÚU»Ø
ÌÍæ âæðçÇUØ× ¥æØÙ (Na+) ·ð¤ ÂýçÌ Ü»Ö» ¥ÂæÚU»Ø ãUæðÌè ã
·é¤ÀU ¥ÙæÁæð´ Áñâð ç·¤ ¿æßÜ (ææÙ) ß »ðãê¡U ×ð´ ÂÚUæ»·¤æ ×éQ¤ ãUæðÙð ·ð¤
ÕæÎ ¥ÂÙè ÁèßÙ ÿæ×Ìæ ....... ×ð´ ¹æð ÎðÌð ãñÚ (1) 30 âð·¤ÇU
(2) 30 ç×ÙÅU
(3) 30 æÅðU
(4) 30 çÎÙ
·¤ß·¤ ÂæÎÂæð´ ·ð¤ âæÍ âãUÁèßè â´Õ´æ ÕÙæÙð ·ð¤ çÜ° ÁæÙð ÁæÌð ãñUÐ §Uâ
â´ØæðÁÙ ×ð´ ·¤ß·¤èØ âãUÁèßè ×ëÎæ ×ð´ È¤æòSÈ¤æðÚUâ ·¤æ ¥ßàææðáæ ·¤ÚU
©Uâð ÂæÎÂæð ×ð´ ÖðÁ ÎðÌð ãñUÐ §Uâ·ð¤ ¥çÌçÚUQ¤ °ðâð â´Õ´ææð´ ØéQ¤ ÂæÎÂæð´ ·¤æð
·¤§üU ¥Ø ÜæÖ Öè ãUæðÌð ãñUÐ °ðâð â´ØæðÁÙ ÎàææüÙð ßæÜð ÂæÎÂæð´ ·¤æð çÙÙ ×ð´
âð ·¤æñÙâæ ÜæÖ ÙãUè´ ãUæðÌæ ãñU (1) ×êÜæßæÌæðÉ¸U (root-borne) ÚUæð»ÁÙ·¤ ·ð¤ ÂýçÌ ÂýçÌÚUæðæ·¤Ìæ
(2) ÜßæÌæ ·ð¤ ÂýçÌ âãUÙàæèÜÌæ
(3) âê¹ð ·ð¤ ÂýçÌ âãUÙàæèÜÌæ
(4) ·¤ß·¤ ÚUæð»ÁÙ·¤ âð ÂýçÌÚUæðæ·¤Ìæ
ÂèØêá »ýçÍ ·ð¤ â´ÎÖü ×ð´ Ùè¿ð çÎØð »Øð ·¤ÍÙæð´ ×ð´ âð ç·¤ÌÙð ·¤ÍÙ âØ
ãñU(i) ÂèØêá »ýçÍ SÈ¤èÙæò§UÇU ¥çSÍ ·ð¤ °·¤ âðÜæ ÅUçâü·¤æ Ùæ×·¤ ¥çSÍÜ
»éãUæ ×ð´ çSÍÌ ãUæðÌè ãñU
(ii) ¥æ´ÌçÚU·¤è ·ð¤ ¥ÙéâæÚU ÂèØêá »ýçÍ °çÇUÙæðãUæ§UÂæðÈ¤æ§Uçââ ¥æñÚU
ØêÚUæðãUæ§UÂæðÈ¤æ§Uçââ Ùæ×·¤ Îæð Öæ»æð´ ×ð´ çßÖæçÁÌ ãUæðÌè ãñU
(iii) Âæâü §UçÅUÚUç×çÇUØæ °·¤×æææ ãUæ×æðÙ
ü ×ðÜÙð æðâæ§UÅU ÂýÚð U·¤ ãUæ×æðÙü (MSH)
SææçßÌ ·¤ÚUÌè ãñU
(iv) Âà¿ ÂèØêá »ýçÍ Îæð ãUæ×æðüÙ ¥æòâèÅUæðçâÙ ÌÍæ ßðâæðÂýðçâÙ ·¤æ
â´»ýã ÌÍæ âýæß ·¤ÚUÌè ãñU
(1) °·¤
(2) Îæð
(3) ÌèÙ
(4) âæè âãUè ãñU
19
Full Syllabus-IV
88. Which feature enables the mammalian kidney to concen- 88.
trate urine in the medullary region (1) Maintaining a high osmotic pressure in the medullary
·¤æñÙâæ Üÿææ SÌçÙØæð´ ·ð¤ ßë·¤æð´ ·¤æð ×Øæ´àæ ÿæñæ ×ð´ ×êæ ·¤æð âæçÎýÌ
·¤ÚUÙð ØæðØ ÕÙæÌæ ãñU(1) ×Øæ´àæ ÿæðæ ×ð´ ØêçÚUØæ ·ð¤ ·¤æÚUæ ©U¿ ÂÚUæâÚUæ ÎæÕ ÕÙæØð ÚU¹Ùæ
region due to urea
(2) Rapid removal of sodium ion from the medullary tis-
(2) ×Øæ´àæ
©Uæ·¤æð´ âð âæðçÇUØ× ¥æØÙæð´ ·¤æ Ìèßý çÙc·¤æâÙ
(3) ×Øæ´àæ
ÿæðæ ×ð´ ÂýæðÅUèÙ ·ð¤ ·¤æÚUæ ©U¿ ÂÚUæâÚUæ ÎæÕ ÕÙæØð ÚU¹Ùæ
sues
(3) Maintaining a high osmotic pressure due to proteins in
medullary region
(4) ×Øæ´àæ ·¤æðçàæ·¤æ¥æð´ ·¤æ ©U¿ ¥æòâè·¤æÚUè ©UÂæÂ¿Ø
(4) High oxidative metabolism of medullary cells
89. Canal of Schelemm is present at the junction of
89.
(1) sensory and nonsensory retina
(2) choroid and ciliary body
(3) junction of sclera and cornea
(4) ciliary body and iris
90. Deltoid ridge of humerus is meant for (1) Articulation with glenoid cavity
(2) Attachement of muscles
(3) passage of blood vessels
(4) None of these
/+1
90.
àÜè× ·¤è ÙæÜ ·¤ãUæ¡ ©UÂçSÍÌ ãUæðÌè ãñU(1) â´ßðÎè ÌÍæ ¥â´ßðÎè ÚÔUçÅUÙæ ·¤è â´çæ SÍÜ ÂÚU
(2) ·¤æðÚUæð§UÇU ÌÍæ çâçÜ°ÚUè ·¤æØ ·ð¤ â´çæ SÍÜ ÂÚU
(3) SÜðÚUæ ÌÍæ ·¤æòçÙüØæ ·ð¤ â´çæ SÍÜ ÂÚU
(4) çâçÜ°ÚUè ·¤æØ ÌÍæ ¥æ§UçÚUâ ·ð¤ â´çæ SÍÜ ÂÚU
sê×ÚUâ ¥çSÍ ·¤æ ÇðUËÅUæò§UÇU ©UÖæÚU ç·¤â·ð¤ çÜ° ÕÙæ ãñU(1) ÜèÙæò§UÇU »éãUæ âð â´çæ ·ð¤ çÜ°
(2) ÂðçàæØæð´ ·ð¤ ÁéÇ¸Ùð ·ð¤ çÜ°
(3) ÚQ¤ ßæçãUçÙØæð´ ·ð¤ çÜ°
20
Full Syllabus-IV
91. The time dependence of a physical quantity P is found to 91.
2
be of the form
2 = 2O A −αJ
°·¤ ÖæñçÌ·¤ ÚUæçàæ P ·¤è â×Ø ÂÚU çÙÖüÚUÌæ
P = PO e −αt mUæÚUæ Îè ÁæÌè ãñUÐ
2
where t is time and α is some constant. Then the constant
ÁãUæ¡ t â×Ø ÌÍæ α °·¤ çÙØÌæ´·¤ ãñU Ìæð çÙØÌæ´·¤ α ãUæð»æ -
α will (1) çß×æãUèÙ
(1) Be dimensionless
horizontal rough surface is shown in figure.
·¤è çß×æ ßæÜæ
(3) P ·¤è çß×æ ßæÜæ
(4) P ·¤æ T ·ð¤ »éæÙÈ¤Ü ·¤è çß×æ ßæÜæ
10 kg ÎýÃØ×æÙ °·¤ »éÅU·¤æ ÿæñçÌÁ ¹éÚUÎÚUè âÌãU ÂÚU ç¿ææÙéâæÚU
m/s ·ð¤ ßÚUæ âð »çÌàæèÜ ãñUÐ
The value of coefficient of kinetic friction is -
»çÌ·¤ æcæüæ »éææ´·¤ ·¤æ ×æÙ ãUæð»æ-
(1) 0.
(1) 0.
( ) 0.4
( ) 0.4
(3) 0.5
(3) 0.5
(4) 0.1
(4) 0.1
( ) Have dimensions of T

( ) T
(3) Have dimensions of P
(4) Have dimensions of P multiplied by T
9 . A block of mass 10 kg, moving with acceleration m/s on 9 .
93. A ball is dropped on a horizontal surface from height h. If it 93.
rebounds upto height
D
after first collision then coefficient
2
of restitution between ball and surface is -
1
(1)
°·¤ »ð´Î ·¤æð h ª¡¤¿æ§üU âð ÿæñçÌÁ æÚUæÌÜ ÂÚU ç»ÚUæØæ ÁæÌæ ãñUÐ ØçÎ æÚUæÌÜ
âð ÂýÍ× ÅUP¤ÚU ·ð¤ Âà¿ææ÷ ØãU
1
2
( )
1
2
( )
1
2
(3)
1
4
(3)
1
4
(4)
1
(4)
2 2
94. The moment of inertia about an axis passing through centre 94.
of mass of system would be (as compared to any other
ª¡¤¿æ§üU Ì·¤ ª¤ÂÚ ©UÆUð ÌÕ æÚUæÌÜ ß
»ð´Î ·ð¤ ×Ø ÂýØæßSÍæÙ »éææ´·¤ ·¤æ ×æÙ ãUæð»æ(1)
2
h
2
1
2 2
°·¤ çÙ·¤æØ ·ð¤ ÎýÃØ×æÙ ·ð¤Îý âð »éÁÚUÌè ¥ÿæ ·ð¤ ÂýçÌ çÙ·¤æØ ·¤æ ÁÇ¸ß
¥ææêæü ¥Ø â×æÌÚU ¥ÿæ ·ð¤ ÂýçÌ ÁÇ¸ß ¥ææêæü ·¤è ÌéÜÙæ ×ð´ ãUæð»æ -
parallel axis.)
(1) ·¤×
(1) Least
( ) Maximum
(3) Average
(4) Least or maximum depending on sense of rotation
/+1
âð ·¤×
( ) ¥çæ·¤Ì×
(3) ¥æñâÌ
(4) ·¤× âð ·¤× Øæ ¥çæ·¤Ì× ãUæðÙæ æêæüÙ ·ð¤ Âý·¤æÚU ÂÚU çÙÖüÚU ·¤ÚÔU»æ
21
Full Syllabus-IV
(1) zero
°·¤ ¥æò»üÙ Âæ§UÂ ×ð´ ÕÙÙð ßæÜè ·ý¤×æ»Ì ¥Âý»æ×è ÌÚÚ»æð´ ·¤è ¥æßëçÌ
150 Hz, 5 Hz, 300 Hz ãñUÐ Âæ§UÂ ·¤æð ÂãU¿æçÙ° ÌÍæ 15th â´ÙæÎè
·¤æ ×æÙ ãUæð»æ(1) 11 5 Hz, ¹éÜè
( ) 11 5 Hz, Õ´Î
(3) 75 Hz, Õ´Î
(4) 675 Hz, ¹éÜè
°·¤ â×æÙ ¥æßðçàæÌ R çæØæ ·ð¤ ÆUæðâ ·é¤¿æÜ·¤ »æðÜð ·ð¤ ·ð¤Îý âð
R ÎêÚUè ÂÚU çßléÌ ÿæðæ ·¤è ÌèßýÌæ E ãñUÐ ·ð¤Îý âð R/ ÎêÚUè ÂÚ çßléÌ
ÿæðæ ·¤è ÌèßýÌæ ãæð»è(1) àæêØ
( )
( )
95. The successive frequencies of standing waves setup in an 95.
organ pipe are 150 Hz,
5 Hz, 300 Hz. Identify the pipe
and find the frequency of 15th harmonic.
(1) 11 5 Hz, open
( ) 11 5 Hz, close
(3) 75 Hz, open
(4) 675 Hz, open
96. The electric field at R from the centre of a uniformly 96.
charged nonconducting sphere of radius R is E. The
electric field at a distance R/ from the centre will be E
E
(3) 4 E
(3) 4 E
(4) 16 E
(4) 16 E
97. The value of alternating emf E in the given circuit will be- 97.
çÎØð »Øð ÂçÚUÂÍ ãðUÌé ÂýØæßÌèü çßléÌ ßæãU·¤ ÕÜ E ·¤æ ×æÙ ãUæð»æ -
(1) 100 V
(1) 100 V
( ) 0V
( ) 0V
(3)
(3)
0V
(4) 140 V
0V
(4) 140 V
98. The apparent coefficient of volume expansion of a liuqid 98.
when heated in a copper vessel is C and when heated in a
silver vessel is S. If A is the linear coefficient of expansion
of copper, then the linear coefficient of expansion of silver
ÁÕ °·¤ Îýß ·¤æð Ìæ¡Õð ·ð¤ Âææ ×ð´ »×ü ç·¤Øæ ÁæÌæ ãñU Ìæð Îýß ·¤æ ¥æÖæâè
¥æØÌÙ ÂýâæÚU »éææ´·¤ C ÌÍæ ¿æ´Îè ·ð¤ Âææ ×ð´ »×ü ·¤ÚUÙð ÂÚU ¥æÖæâè
¥æØÌÙ ÂýâæÚU »éææ´·¤ S ãñUÐ ØçÎ Ìæ¡Õð ·¤æ ÚÔUç¹Ø ÂýâæÚU »éææ´·¤ A ãUæð Ìæð
¿æ´Îè ·¤æ ÚÔUç¹Ø ÂýâæÚU »éææ´·¤ ãUæð»æ -
is (1)
C + S − 3A
3
(1)
C + S − 3A
3
( )
C + 3A − S
3
( )
C + 3A − S
3
(3)
S + 3A − S
3
(3)
S + 3A − S
3
(4)
C + S + 3A
3
(4)
C + S + 3A
3
/+1
22
Full Syllabus-IV
ª¤¡¿æ§üU âð °·¤ ÙÎè ×ð´ ·é¤ÎÌæ ãéU¥æ ÌñÚUæ·¤ ¥æâæÙè âð ãßæ ×ð´ ÜêÂ ÕÙæÌæ
ãñU, ØçÎ(1) ßãU ¥ÂÙè ÖéÁæ¥æð´ ÌÍæ ÂñÚUæð ·¤æð ¥ÎÚU ¹è´¿Ìæ ãñU
( ) ßãU ¥ÂÙè ÖéÁæ¥æð´ ÌÍæ ÂñÚUæð ·¤æð È¤ñÜæÌæ ãñU
(3) ßãU Sß´Ø ·¤æð âèææ ÚU¹Ìæ ãñU
(4) §UÙ×´ð âð ·¤æð§üU ÙãUè´
100. °·¤ Âý·¤æàæ ç·¤ÚUæ Âé´Á ×ð´ ÜæÜ ¥æñÚU ãUÚUè ç·¤ÚUæð´ ãñUÐ ØãU ç·¤ÚUæ Âé´Á °·¤
¥æØÌæ·¤æÚU ·¤æ¡¿ ·ð¤ »éÅU·ð¤ ·¤è âÌãU ÂÚU çÌÚUÀUæ ¥æÂçÌÌ ãUæðÌæ ãñU ¥æñÚU
â×é¹ È¤Ü·¤ âð çÙ»üÌ ãUæðÌæ ãñUÐ ÜæÜ ¥æñÚU ãUÚUè ç·¤ÚUæð´-
99. A swimmer while jumping into river from a height easily 99.
forms a loop in air if
(1) He pulls his arms and legs in
( ) He spreads his arms and legs
(3) He keeps himself straight
(4) None of these
100. A beam of light composed of red and green ray is incident
obliqely at a point on the face of rectangular glass slab.
When coming out on the oppsite parallel face, the red and
green ray emergy from (1) Two point propagating in two different directions
( ) Two point propagating in two parallel directions
(3) One point propagating in two different directions
(4) One point propagating in same directions
101. Drops of liquid of density ρ are floating half immersed in a
liquid of density σ. If the surface tension of liquid is T, the
(1) Îæð
çßçÖóæ çÕÎé¥æð´ âð Îæð çßçÖóæ ¥â×æÌÚU çÎàææ¥æð´ ×ð´ çÙ»üÌ ãUæ»´ð è
( ) Îæð çÕÎé¥æð´ âð´ Îæð â×æÌÚU çÎ¹æ¥æ´ð ×ð´ çÙ»üÌ ãUæð»è
(3) °·¤ ãUè çÕÎé âð Îæð çßçÖóæ çÎàææ¥æð´ ×ð´ SÜñÕ âð çÙ»üÌ ãUæð»è
(4) °·¤ ãUè çÕÎé °·¤ ãUè çÎàææ ×ð´ SÜñÕ âð çÙ»üÌ ãUæð»è
101. ρ æÙß ·¤è Îýß ·¤è Õé´Îð σ æÙß ·ð¤ Îýß ×ð´ ¥ææè ÇéUÕè ãéUØè ãñU T Îýß
·¤æ ÂëçDUØ ÌÙæß ãñU, Ìæð Õê´Î ·¤è çæØæ ææÌ ·¤èçÁ° -
radius of the drop will be (1)
3T
g 3ρ − σ
g
(1)
3T
g 3ρ − σ
g
( )
6T
g 2ρ − σ
g
( )
6T
g 2ρ − σ
g
(3)
3T
g 2ρ − σ
g
(3)
3T
g 2ρ − σ
g
(4)
3T
g 4 ρ − 3σ
(4)
3T
g 4 ρ − 3σ
b
b
b
b
g
b
b
b
b
g
10 . With what velocity v0 should a ball projected horizontally 10 . °·¤
the ground is nH, where H is the height of the tower -
×èÙæÚU ·ð¤ àæèáü âð °·¤ »ð´Î ·¤æð v0 ßð» âð ÿæñçÌÁ ÂýÿæðçÂÌ ç·¤Øæ
ÁæÌæ ãñU ç·¤ æÚUæÌÜ ÂÚU ØãU nH ÿæñçÌÁ ÎêÚUè ÂÚ ç»ÚUÌè ãñU, ÁãUæ¡ H ×èÙæÚU
·¤è ª¡¤¿æ§üU ãñU, ßð» v0 ãUæð»æ-
(1) n 2gH
(1) n 2gH
( ) n gH
( ) n gH
from the top of a tower so that the horizontal distance on
(3)
n
gH
2
(4) n
/+1
gH
2
(3)
n
gH
2
(4) n
gH
2
23
Full Syllabus-IV
103. Two particles of equal mass m are moving round a circle 103. â×æÙ ÎýÃØ×æÙ m ·ð¤ Îæð ·¤æ r çæØæ ·ð¤ ßëÌèØ ÂÍ ×ð´ ÂÚUSÂÚU ¥ØæðØ
of radius r due to their mutual gravitational interaction. Find
»éM¤ßèØ ç·ý¤Øæ ·ð¤ ·¤æÚUæ »çÌ ·¤ÚU ÚãðÚ ãñUÐ ÂýØð·¤ ·¤æ ·¤è ¿æÜ ãUæð»è-
the speed of each particle -
Gm
r
(1)
Gm
r
(1)
( )
Gm
2r
( )
Gm
2r
(3)
1 Gm
2
r
(3)
1 Gm
2
r
(4) ·¤æð§üU
(4) None
104. A particle starts S.H.M. from the mean position. Its
amplitude is A and time period is T. At the time when its
speed is half of the maximum speed, its displacement y is
(1)
( )
(3)
(4)
A
2
ÙãUè´
104. °·¤ ·¤æ ×æØ çSÍçÌ âð âÚUÜ ¥æßëÌ »çÌ ÂýæÚUÖ ·¤ÚUÌæ ãñUÐ §Uâ·¤æ
¥æØæ× A ÌÍæ ¥æßÌü ·¤æÜ T ãñÐ ßãU ÿææ ÁÕ §Uâ·¤è ¿æÜ ¥çæ·¤Ì×
¿æÜ ·¤è ¥ææè ãUæð ÌÕ ©Uâ ÿææ ·¤æ ·¤æ çßSÍæÂÙ y ãUæð»æ(1)
A
( )
2
A 3
2
(3)
2A
(4)
3
A
2
A
2
A 3
2
2A
3
105. Calculate the velocity (approx.) of sound in a gas in which 105. ßãU »ñâ çÁâ×ð´ 04 cm ÌÍæ 08 cm ÌÚÚ»ÎñØü ßæÜè ÌÚÚ»ð´ 0 çßSÂ´Î
two wavelengths 04 cm and 08 cm produce 0 beats in
6
âñ·¤ÇU ×ð´ ©UÂÙ ·¤ÚÔU, ©Uâ×ð´ ßçÙ ·¤æ ßð» (Ü»Ö») ãUæð»æ -
6 seconds (1) 330 m/s
(1) 330 m/s
( ) 300 m/s
( ) 300 m/s
(3) 04 m/s
(3) 04 m/s
(4) 354 m/s
(4) 354 m/s
/+1
24
Full Syllabus-IV
106. A fully charged capacitor has a capacitance 'C'. It is 106. °·¤
discharged through a small coil of resistance wire
embedded in a thermally insulated block of specific heat
capacity 's' and mass 'm'. If the temperature of the block
is raised by '∆T', the potential difference 'V' across the
Âêæü ¥æßðçàæÌ â´ææçÚUÌ ·¤è ææçÚUÌæ 'C' ãñUÐ §Uâ·¤æð ÂýçÌÚUæðæ ÌæÚU
·¤è °·¤ ÀUæðÅUè ·é¤ÇUÜè Áæð çßçàæCU ª¤c×æ 's' ÌÍæ ÎýÃØ×æÙ 'm'
ßæÜð ÌæÂèØ çßÜç»Ì »éÅU·ð ×ð´ æ´âè ãéUØè ãñU mUæÚUæ ¥ÙæßðçàæÌ ç·¤Øæ
ÁæÌæ ãñUÐ ØçÎ ¤»éÅU·ð¤ ·ð¤ ÌæÂ×æÙ ×ð´ ßëçhU '∆T' ãUæð Ìæð â´ææçÚUæ ·ð¤
çâÚUæð´ ÂÚU çßÖßæÌÚU 'V' ãUæð»æ-
capacitor is (1)
msDT
C
(1)
msDT
C
( )
2msDT
C
( )
2msDT
C
(3)
2mCDT
s
(3)
2mCDT
s
(4)
mCDT
s
(4)
mCDT
s
107. In a series LCR circuit R = 00 Ω and the voltage and the 107. °·¤ æðæè LCR ÂçÚUÂÍ ×ð´ R = 00 Ω ÌÍæ ×éØ SææðÌ ·¤æ çßÖßæÌÚU
frequency of the main supply is
0 V and 50 Hz
respectively. On taking out the capacitance from the circuit
the current lags behind the voltage by 30º. On taking out
the inductor from the circuit the current leads the voltage
ß ¥æßëÌèü ·ý¤×àæÑ 0 V ÌÍæ 50 Hz ãñUÐ ÂçÚUÂæ âð â´ææçÚUæ ·¤æð ãUÅUæÙð
ÂÚU ææÚUæ çßÖßæÌÚU ·ð¤ 30º ¥Ùé»æ×è ãUæðÌè ãñUÐ ÂçÚUÂÍ âð ÂýðÚU·¤ß ·¤æð
ãUÅUæÙð ÂÚU ææÚUæ çßÖßæÌÚU ·ð¤ 30º ¥»ý»æ×è ãUæðÌè ãñUÐ LCR ÂçÚUÂÍ ×ð´
ÿæçØÌ àæçQ¤ ãUæð»è -
by 30º. The power dissipated in the LCR circuit is (1) 4 W
(1) 4 W
( ) 305 W
( ) 305 W
(3) 10 W
(3) 10 W
(4) Zero W
(4) àæêØ W
108. Find VAB
108. VAB
ææÌ ·¤èçÁ° -
(1) 10 V
(1) 10 V
( ) 0V
( ) 0V
(3) 30 V
(3) 30 V
(4) None of these
(4) §UÙ×ð´
/+1
âð ·¤æð§üU ÙãUè´
25
Full Syllabus-IV
of descent through, AB, BC and CD are in ratio:
ª¤ßæüæÚU ÚÔU¹æ ÂÚU §Uâ Âý·¤æÚU çÕÎé ãñÚ ç·¤
AB = BC=CD ãñUÐ ØçÎ °·¤ ßSÌé ·¤æð A âð çßÚUæ×æßSÍæ âð ç»ÚUæØæ
ÁæØð Ìæð AB, BC ÌÍæ CD ·¤æð ÌØ ·¤ÚUÙð ·ð¤ â×Ø ·¤æ ¥ÙéÂæÌ ãUæð»æ -
(1) 1: 2 : 3
(1) 1: 2 : 3
( ) 2 : 3 :1
( ) 2 : 3 :1
(3) 3 :1: 2
(3) 3 :1: 2
109. A, B, C and D are points in a vertical line such that
AB = BC=CD. If a body falls from rest at A, then the times
(4) 1:
e
je
2 −1 :
3− 2
j
109. A, B, C ÌÍæ D °·¤
(4) 1:
e
je
2 −1 :
110. How many grams of a liquid of specific heat 0. at a 110. 40°C ÂÚU
3− 2
j
çSÍÌ 0. çßàæCU ª¤c×æ ßæÜð Îýß ·ð¤ ç·¤ÌÙð »ýæ×,
temperature 40°C must be mixed with 100 gm of a liquid
çSÍÌ
of specific heat of 0.5 at a temperature 0°C, so that the
ç×ææ ·¤æ ÌæÂ 3
0.5
çßçàæCU ª¤c×æ ßæÜð
°C
100
0°C ÂÚU
»ýæ× Îýß ×ð´ ç×ÜæØð ÁæØð Ìæç·¤
ãUæð ÁæØð -
final temperature of the mixture becomes 3 °C (1) 175 gm
(1) 175 gm
( ) 300 g
( ) 300 g
(3) 95 gm
(3) 95 gm
(4) 375 g
(4) 375 g
111. Two tree are at distance of 3.14 m from each other. What 111. Îæð ßëÿæ °·¤ ÎêâÚÔU âð 3.14 m ·¤è ÎêÚUè ÂÚU çSÍÌ ãñUÐ °·¤ Âýðÿæ·¤ ßëÿææð´ âð
should the maximum distance of an observer from tree to
ç·¤ÌÙè ¥çæ·¤Ì× ÎêÚUè ÂÚU ¹ÇU¸æ ãUæð·¤ÚU §UãðÚ ¥Ü»-¥Ü» Îð¹ â·¤Ìæ
see them separately -
ãñU -
(1) 1.6 km
(1) 1.6 km
( ) 10.8 km
( ) 10.8 km
(3) 15 km
(3) 15 km
(4) 5. km
(4) 5. km
H
H
H
11 . If vector F be a force acting on a particle having the position 11 . ØçÎ âçÎàæ F ßãU ÕÜ ãñ Áæð r çSÍçÌ âçÎàæ ßæÜð ·¤æ ÂÚU Ü»æ
H
H
H
vecotor r and τ be the torque of this force about the origin,
ÌÍæ τ §Uâ ÕÜ ·¤æ ×êÜ çÕÎé ·ð¤ ÂçÚUÌÑ ÕÜ-¥ææêæü ãñUÐ ÌÕthen
H H
(1) r ⋅ τ =
H H
( ) r ⋅τ =
H H
(3) r ⋅ τ ≠
H H
(4) r ⋅ τ ≠
/+1
H H
0 and . ⋅ τ = H H
0 and . ⋅ τ ≠ H H
0 and . ⋅ τ ≠ H H
0 and . ⋅ τ = H H
(1) r ⋅ τ
H H
( ) r ⋅τ
H H
(3) r ⋅ τ
H H
(4) r ⋅ τ
=0
ÌÍæ
=0
ÌÍæ
≠0
ÌÍæ
≠0
ÌÍæ
H H
. ⋅τ = H H
. ⋅τ ≠ H H
. ⋅τ ≠ H H
. ⋅τ = DTS (Daily Test Series) for Re-AIPMT- 2015
26
ãñU
Full Syllabus-IV
113. A train moves towards a stationary observer with a speed 113. °·¤
34 m/s. The train sounds a whistle and its frequency
registered by the observer is f1. If the speed of the train is
reduced to 17 m/s, the frequency registered is f . If the
f
speed of sound is 340 m/s then the ratio is f2
ÚÔUÜ»æÇ¸è çSÍÚU Âýðÿæ·¤ ·¤è ¥æðÚU 34 m/s ·¤è ¿æÜ âð »çÌàæèÜ ãñUÐ
ÚÔUÜ»æÇ¸è ãUæòÙü ÕÁæÌè ãñU ÌÍæ Âýðÿæ·¤ mUæÚUæ §Uâ·¤è ÂýðçÿæÌ ¥æßëçÌ f1 ãñUÐ
ØçÎ ÚÔUÜ»æÇ¸è ·¤è ¿æÜ 17 m/s ãUæð Ìæð Âýðÿæ·¤ mUæÚUæ ÂýðçÿæÌ ¥æßëçÌ f ãñUÐ
ØçÎ ßçÙ ·¤è ¿æÜ 340 m/s ãUæð Ìæð ¥ÙéÂæÌ
(1)
18
19
(1)
18
19
( )
1
2
( )
1
2
(3)
(4)
f
f2
·¤æ ×æÙ ãUæð»æ-
(3)
19
18
(4)
H
114. An electric field E = i 20 + j30 newton/coulomb exists in 114. °·¤
e
j
19
18
çßléÌ ÿæðæ
H
E = i 20 + j30
e
j ØêÅUÙ/·ê¤Üæò×Ð ØçÎ ×êÜ çÕÎé
find the potential at ( m, m)
ÂÚU çßÖß ·¤æð àæêØ ×æÙæ ÁæØð Ìæð çÕÎé
ãUæð»æ-
(1) + 100 V
(1) + 100 V
( ) 100 V
( ) 100 V
(3) 50 V
(3) 50 V
(4) 50 V
(4) 50 V
the space. If the potential at the origin is taken to be zero,
( m, m)
ÂÚU çßÖß
115. What is the approximate peak value of an alternating current 115. ÂýØæßÌèü ææÚUæ ·¤æ çàæ¹ÚU ×æÙ Ü»Ö» ç·¤ÌÙæ ãUæð»æ ØçÎ ÂýØæßÌèü ææÚUæ
producing four times the heat produced per second by a
mUæÚUæ ç·¤âè ÂýçÌÚUæðæ ×ð´ ©UÂóæ àæçQ¤
steady current of .0 A in resistor -
àæçQ¤ ·¤è ¿æÚU »éÙæ ãUæð»è -
(1) .8 A
(1) .8 A
( ) 4.0 A
( ) 4.0 A
(3) 5.6 A
(3) 5.6 A
(4) 8.0 A
(4) 8.0 A
116. A vessel contains 1 mole of O gas (molar mass 3 ) at a 116. °·¤
.0 A
·¤è SÍæ§üU ææÚUæ mUæÚUæ ©UÂóæ
Âææ ×ð´ °·¤ ×æðËæ O »ñâ (¥æçß·¤ ÎýÃØ×æÙ 3
) T ÌæÂ×æÙ
ÂÚU
temperature T. The pressure of the gas is P. An identical
ÖÚUè ãñUÐ »ñâ ·¤æ ÎæÕ P ãñUÐ â×æÙ Âææ ×ð´ °·¤ ×æðËæ He »ñâ (¥æçß·¤
vessel containing one mole of He gas (molar mass 4) at
ÎýÃØ×æÙ 4) ÌæÂ×æÙ
T
ÂÚU ÖÚUè ãñU Ìæð ãUèçËæØ× ·¤æ ÎæÕ ãUæð»æ -
temperature T has a pressure of (1) P/8
(1) P/8
( )P
( )P
(3) P
(3) P
(4) 8P
(4) 8P
/+1
27
Full Syllabus-IV
117. A rod of length 10 cm lies along the principal axis of a 117. 10 cm ÜÕè °·¤ ÀUÇ¸ ·¤æð, 10 cm È¤æð·¤â ÎêÚUè ·ð¤ °·¤ ¥ßÌÜ ÎÂüæ
concave mirror of focal length 10 cm in such a way that its
·¤è ×éØ ¥ÿæ ·ð¤ ¥ÙéçÎàæ §Uâ Âý·¤æÚU ÚU¹æ ÁæÌæ ãñU ç·¤ ÀUÇ¸ ·¤æ ÎÂüæ ·ð¤
end closer to the pole is 0 cm away from the mirror. The
æýéß ·ð¤ Âæâ ßæÜæ çâÚUæ, ÎÂüæ âð
length of the image is -
ÜÕæ§üU ãUæð»è -
(1) 10 cm
(1) 10 cm
( ) 15 cm
( ) 15 cm
(3) .5 cm
(3) .5 cm
(4) 5 cm
(4) 5 cm
0 cm
ÎêÚU ãñU, Ìæð ÂýçÌçÕÕ ·¤è
118. In young double slit experiment if distance between sources 118. ØçÎ Ø´» çmU çSÜÅU ÂýØæð» ×ð´ âýæðÌæð´ ·ð¤ ×Ø ÎêÚUè ·¤æð Îé»éÙæ ·¤ÚU çÎØæ ÁæØð
is made double then central fringe width will be -
Ìæð ·ð¤ÎýèØ çÈý¤Á ·¤è ¿æñÇ¸æ§üU ãUæð ÁæØð»è -
(1) half
(1) ¥ææè
( ) double
( ) Îé»éÙè
(3) unchanged
(3) ¥ÂçÚUßçÌüÌ
(4) nothing can be said
(4) ·é¤ÀU
moved along x-axis with constant speed 1 ms1. Then
·ð¤ ¥ÙéçÎàæ çÙØÌ ¿æÜ
induced e.m.f. in the rod is -
çßléÌ ßæãU·¤ ÕÜ ãUæð»æ-
(1) Zero
(1) àæêØ
( ) 5 V
( ) 5 V
(3) 5 V
(3) 5 V
(4) 10 V
(4) 10 V
ÙãUè´ ·¤ãUæ Áæ â·¤Ìæ
H
119. A uniform magnetic field exists in the region given by 119. â×çcÅ ×ð´ â×M¤Â ¿éÕ·¤èØ ÿæðæ B = 3i + 4 j + 5k âð çÎØæ ÁæÌæ ãñÚÐ
H
5m Üææ§üU ·¤è ÀUÇ¸ Áæð y-¥ÿæ ·ð¤ ¥ÙéçÎàæ ÚU¹è ãéUØè ãñU, ÌÍæ x-¥ÿæ
B = 3i + 4 j + 5k . A rod of length 5m placed along y-axis is
1 ms1
»çÌ ·¤ÚU ÚUãUè ãñU Ìæð ÀUÇ¸ ×´ð ÂýðçÚUÌ
1 0. A long wire carrying current I and other carrying I in the 1 0. Îæð ÜÕð ææÚUæßæãUè ÌæÚU çÁÙ×ð´ ææÚUæ I ÌÍæ
same direciton produce a magnetic field B at the mid-point.
What will be the field when I wire is switched off ?
I â×æÙ çÎàææ ×ð´ ÂýßæçãUÌ ãUæð
ÚUãUè ãñ ·ð¤ ×Ø çÕÎé ÂÚU ©æóæ ¿éÕ·¤èØ ÿæðæ B ãñUÐ ØçÎ ÌæÚU çÁâ×ð´
I
ææÚUæ ÂýßæçãUÌ ãUæð, ·¤æð ÕÎ ·¤Ú çÎØæ ÁæØð Ìæð ×Ø çÕÎé ÂÚU
¿éÕ·¤èØ ÿæðæ ãUæð»æ(1)
B
2
(1)
B
2
( ) B
( ) B
(3) B
(3) B
(4) 4 B
(4) 4 B
/+1
28
Full Syllabus-IV
ÎýÃØ×æÙ ß q ¥æßðàæ ·¤æ ·¤æ rçæØæ ·ð¤ ßëÌæ·¤æÚU ÂÍ ×ð´ ÌÜ ·ð¤
ÜÕßÌ ¿éÕ·¤èØ ÿæðæ B ×ð´ ¿·¤ÚU Ü»æ ÚUãUæ ãñÚÐ ·¤æ ·¤æð °·¤ ¿·ý¤
ÂêÚUæ ·¤ÚUÙð ×ð´ Ü»æ â×Ø ãUæð»æ-
121. A charge particle of mass m and charge q revolves on 1 1. m
circular path of radius r in a perpendicular magnetic field
B. The time taken by the particle to complete the revolution
is (1)
2 πqB
m
(1)
2 πqB
m
(2)
2πm
qB
( )
2πm
qB
(3)
2 π mq
B
(3)
2 π mq
B
(4)
mq
2 πB
(4)
mq
2 πB
122. Two wires A and B of equal masses and of the same metal 1
. Îæð °·¤ â×æÙ ææÌé âð ÕÙð ÌæÚU A ÌÍæ B ·¤æ ÎýÃØ×æÙ Öè â×æÙ ãñÐ ÌæÚU
are taken. The diameter of the wire A is half the diameter
A ·¤æ ÃØæâ ÌæÚU B ·¤è ÌéÜÙæ ×ð´ ¥æææ ãñUÐ ØçÎ ÌæÚU A ·¤æ ÂýçÌÚUæðæ 4Ω
of the wire B. If the resistance of the wire A be 24Ω,
ãUæð, Ìæð ÌæÚU B ·¤æ ÂýçÌÚUæðæ ææÌ ·¤èçÁ°-
calculate the resistance of the wire B.
(1) 3 Ω
(1) 3 Ω
(2) 1.5 Ω
( ) 1.5 Ω
(3) 6 Ω
(3) 6 Ω
(4) 12 Ω
(4) 1 Ω
123. A long straight wire AB carrying a current i. A proton P 1 3. °·¤
travels with a speed v parallel to the wire at a distance d
from it in a direction opposite to the current as shown in
adjoining figure. What is the force experienced by the
ÜÕð âèæð ÌæÚU AB ×ð́ i ææÚUæ ÂýßæçãUÌ ãUæð ÚUãUè ãñUÐ °·¤ ÂýæðÅUæðÙ P
¿æÜ v âð ÌæÚU ·ð¤ â×æÙæÌÚU §Uââð d ÎêÚUè ÂÚU ç¿ææÙéâæÚU ÌæÚU ×ð´ ææÚUæ ·ð¤¤
çßÂçÚUÌ çÎàææ ×ð´ »çÌ ·¤ÚU ÚUãUæ ãñUÐ ÂýæðÅUæðÙ mUæÚUæ ¥ÙéÖß ç·¤Øæ »Øæ ÕÜ
ÕÌæ§UØð -
proton-
(1) F =
µ 0 evi
4π d
(2) F =
µ 0 evi
4 d
(1) F =
µ 0 evi
4π d
(2) F =
µ 0 evi
4 d
(3) F =
µ 0 evi
2 d
(4) F =
µ 0 evi
2π d
(3) F =
µ 0 evi
2 d
(4) F =
µ 0 evi
2π d
/+1
29
Full Syllabus-IV
leaves by the corner R. Then the currents I1 and I2 are -
·¤è ææÚUæ °·¤ â×ÕæãéU çæÖêÁ PQR çÁâ·¤è ÂýØð·¤ ÖêÁæ ×ð´ 2 Ω
ÂýçÌÚUæðæ ç¿ææÙéâæÚU ÁéÇ¸æ ãé¥æ ãñU, ·ð¤ çâÚÔU P ÂÚU ÂýçßCU ãUæðÌè ãñU ÌÍæ çâÚÔU
R âð çÙ»üÌ ãUæðÌè ãñUÐ ææÚUæ I1 ÌÍæ I 2 ·¤æ ×æÙ ãñU -
(1) 2 A, 4 A
(1) 2 A, 4 A
(2) 4 A, 2 A
(2) 4 A, 2 A
(3) 1 A, 2 A
(3) 1 A, 2 A
(4) 2 A, 3 A
(4) 2 A, 3 A
124. A current of 6 A enters one corner P of an equilateral 124. 6 A
triangle PQR having 3 wires of resistances 2 Ω each and
125. In the given circuit, R1 > R2. Power dissipation will be -
125. çÎØð
»Øð ÂçÚUÂÍ ×ð´, R1 > R2 ãñUÐ ¹¿ü àæçQ¤ ãUæð»è -
(1) greater in R1
(1) R1 ×ð´ ¥çæ·¤
(2) greater in R2
(2) R2 ×ð´ ¥çæ·¤
(3) equal in both
(3) ÎæðÙæð´ ×ð´ â×æÙ
(4) Zero
(4) àæêØ
126. An unknown resistance R is connected in series with a 126. ,d
1
vKkr izfrjks/k R1, 10Ω izfrjks/k ds Js.kh ÿe esa tksM+k x;k gSA
resistance of 10 Ω. This combination is connected to one
bl la;kstu dks ehVj lsrq ds igys fjDr LFkku esa tksM+k x;k gS tcfd
gap of a metre bridge while a resistance R is connected
2
vU; izfrjks/k R2 dks nwljs fjDr LFkku essa tksM+k x;k gS] larqyu fcUnq
in the other gap. The balance point is at 50 cm. Now, when
50 lseh ij izkIr gksrk gSA vc ;fn 10Ω
the 10 Ω resistance is removed the balance point shifts to
rks larqyu fcUnq
1/3 m. The value of R is (in ohms) 1
gksxk
(1) 20
(1) 20
(2) 10
(2) 10
(3) 5
(3) 60
(4) 40
(4) 40
/+1
1/3
izfrjks/k dks gVk fn;k tk,
eh- ij izkIr gksrk gS rks R1 dk eku (vkse esa)
30
Full Syllabus-IV
127. Assume that the nuclear binding energy per nucleon (B/A) 127. ×æÙ
Üð´ ç·¤ ØêçÜØæÙ ÙæçÖ·¤èØ Õ´æÙ-ª¤Áæü (B/A) ÕÙæ× ÎýÃØ×æÙ
versus mass number (A) is as shown in the figure. Use this
â´Øæ (A) Ùè¿ð ÎàææüØð »Øð ç¿æ ·ð¤ ¥ÙéâæÚU ãñUÐ §Uâ »ýæÈ¤ ·¤æ ©UÂØæð»
plot to choose the correct choice(s) given below -
·¤ÚUÌð ãéU° âãUè ©UæÚUæð´ ·¤æ ¿éÙæß ·¤ÚÔÚ -
(A) Fusion of two nuclei with mass numbers lying in the
(A) Îæð ÙæçÖ·¤æð´ ·ð¤ â´ÜØÙ ×ð´, çÁÙ·¤è ÎýÃØ×æÙ â´Øæ 1 < A < 50 ·ð¤
range of 1 < A < 50 will release energy
Õè¿ ×ð´ ãñU, ª¤Áæü ·¤æ ©UâÁüÙ ãUæð»æ
(B) Fusion of two nuclei with mass numbers lying in the
(B) Îæð ÙæçÖ·¤æð´ ·ð¤ â´ÜØÙ ×ð´, çÁÙ·¤è ÎýÃØ×æÙ â´Øæ 51 < A < 100
range of 51 < A < 100 will release energy
·ð¤ Õè¿ ×ð´ ãñU, ª¤Áæü ·¤æ ©UâæüÙ ãUæð»æ
(C) Fission of a nucleus lying in the mass range of 100 < A <
(C) °·¤ ÙæçÖ·¤, çÁâ·¤è ÎýÃØ×æÙ â´Øæ 100 < A < 200 ·ð¤ Õè¿ ×ð́
200 will release energy when broken into two equal fragments
ãñU, ·ð¤ Îæð â×æÙ Öæ»æð´ ×ð´ çß¹´ÇUÙ ÂÚU ª¤Áæü ·¤æ ©UâÁüÙ ãUæð»æ
(D) Fission of a nucleus lying in the mass range of 200 < A
(D) °·¤ ÙæçÖ·¤, çÁâ·¤è ÎýÃØ×æÙ â´Øæ 200 < A < 260 ·ð¤ Õè¿ ×ð́
< 260 will release energy when broken into two equal
ãñU, ·ð¤ Îæð â×æÙ Öæ»æð´ ×ð´ çß¹´ÇUÙ ÂÚU ª¤Áæü ·¤æ ©UâÁüÙ ãUæð»æ
fragments
(1) A and B
(1) A ÌÍæ B
(2) A, B and C
(2) A, B ÌÍæ C
(3) B and D
(3) B ÌÍæ D
(4) only D
(4) ·ð¤ßÜ D
128. The K.E. of the photoelectrons is E when the incident 128. ØçÎ
wavelength is λ/2. The K.E. becomes 2E when the incident
wavelength is λ/3. The work function of the metal is -
¥æÂçÌÌ Âý·¤æàæ ·¤è ÌÚÚ»ÎñØ λ/2 ãUæð Ìæð ©UâçÁüÌ §UÜðÅþæòÙ ·¤è
¥çæ·¤Ì× »çÌÁ ª¤Áæü E ãñUÐ ØçÎ ÌÚÚ»ÎñØü λ/3 ãUæð ÁæØð Ìæð »çÌÁ
ª¤Áæü 2E ãUæð ÁæÌè ãñU, Ìæð ·¤æØüÈ¤ÜÙ ÕÌæ§U° -
(1)
hc
l
(1)
hc
l
(2)
2hc
l
(2)
2hc
l
(3)
3hc
l
(3)
3hc
l
(4)
hc
3l
(4)
hc
3l
/+1
31
Full Syllabus-IV
129. The half life of a radioactive nucleus is 50 days. Assuming 129. ç·¤âè
in time t2 nucleus is decayed to
is decayed to
4
of it and in time t1 nucleus
5
1
of it. The time interval (t2 t1) is 5
4
5
ÚÔUçÇUØæð âç·ý¤Ø ÙæçÖ·¤ ·¤è ¥hüU ¥æØé 50 çÎÙ ãñU, Ìæð §Uâ·ð¤
Öæ» ·ð¤ ÿæçØÌ ãUæðÙð ·ð¤ â×Ø
t2 , ÌÍæ
1
Öæ»
5
·ð¤ ÿæçØÌ ãUæðÙð ·ð¤
â×Ø t1, ·ð¤ ×Ø â×Ø ¥ÌÚUæÜ (t2 t 1) ãUæð»æ -
(1) 60 days
(1) 60 days
(2) 15 days
(2) 15 days
(3) 50 days
(3) 50 days
(4) 100 days
(4) 100 days
130. The speed of a homogeneous solid sphere after rolling 130. h ª¡¤¿æ§üU ·ð¤ ÙÌ â×ÌÜ âð çÕÙæ çÈ¤âÜð ÜêÉ¸U·¤Ùð ßæÜð °·¤â×æÙ ÆUæðâ
down an inclined plane of vertical height h, from rest without
»æðÜð ·¤æ Á×èÙ ÂÚU ÂãéU¿Ùð ÂÚU ßð» ãUæð»æ-
siliding is (1)
(2)
(3)
(4)
gh
(1)
FG g IJ gh
H 5K
FG 4 IJ gh
H3K
FG 10 IJ gh
H7K
(2)
(3)
(4)
gh
FG g IJ gh
H 5K
FG 4 IJ gh
H3K
FG 10 IJ gh
H7K
131. A parallel plate capacitor has charge Q on each of its plate 131. °·¤
and electric field intensity between plate of capacitor is E.
Then electric force on each plate of a parallel plate capacitor
â×æÌÚU ÂÅU÷ÅU â´ææçÚUæ ·¤è ÂýØð·¤ ÜðÅU ÂÚU ¥æßðàæ ·¤è ×æææ Q ãñU
ÌÍæ ÜðÅUæð´ ·ð¤ ×Ø çßléÌ ÿæðæ ·¤è ÌèßýÌæ E ãñU, ÌÕ â×æÌÚU ÂÅU÷ÅU
â´ææçÚUæ ·¤è ÂýØð·¤ ÜðÅU ÂÚU çßléÌ ÕÜ ãUæð»æ-
has a magnitude equal to (1) QE
(1) QE
(2) 2QE
(2) 2QE
(3)
1
QE
2
(3)
1
QE
2
(4) ·¤æð§üU ÙãUè´
132. The two ends of a train moving with constant acceleration 132. çÙØÌ ßÚUæ âð »çÌàæèÜ °·¤ ÅðþUÙ ·ð¤ ÎæðÙæð´ çâÚÔU °·¤ çÙçà¿Ì çÕÎé ·¤æð
pass a certain point with velocities u and 3u. The velocity
u ÌÍæ 3u ßð» âð ÂæÚU ·¤ÚUÌð ãñÚÐ ©Uâè çÕÎé ·¤æð ÂæÚU ·¤ÚUÌð â×Ø ÅðþUÙ ·ð¤
(4) None
with which the middle point of the train passes the same
×Ø çÕÎé ·¤æ ßð» ãUæð»æ -
point is :
(1) 2 u
(2)
(3)
3
u
2
5u
(4) 10 u
/+1
(1) 2 u
(2)
(3)
3
u
2
5u
(4) 10 u
32
Full Syllabus-IV
133. A man pulls a bucket full of water from h metre deep well. 133. °·¤
If the mass of rope is m and mass of bucket full of water is
M, then work done by the man is :
FG M + mIJ gh
H2 K
F M + mIJ gh
(2) GH
2 K
F mI
(3) GH M + JK gh
2
ÃØçQ¤ ÁÜ âð æÚUè ÕæËÅè ·¤æð h »ãUÚUæ§üU ßæÜð ·é¡¤° âð ç¹´¿Ìæ ãñUÐ
ØçÎ ÚUSâè ·¤æ ÎýÃØ×æÙ m ÌÍæ ÖÚUè ãéUØè ÕæËÅUè ·¤æ ÎýÃØ×æÙ M ãUæð Ìæð
ÃØçQ¤ mUæÚUæ ç·¤Øæ »Øæ ·¤æØü ãUæð»æ-
FG M + mIJ gh
H2 K
F M + mIJ gh
(2) GH
2 K
F mI
(3) GH M + JK gh
2
(1)
(1)
(4) (M + m)gh
(4) (M + m)gh
134. Force constants K 1 and K2 of two spring are in the ratio 134. Îæð
5 : 4. They are stretched by same length. If potential energy
stored in one spring is 25 J then potential energy stored in
çSÂý´»æð´ ·ð¤ ÕÜ çÙØÌæ´·¤ K1 ÌÍæ K 2 ·¤æ ¥ÙéÂæÌ 5 : 4 ãñUÐ §UÙ·¤æð
â×æÙ ÜÕæ§üU Ì·¤ çßSÌæçÚUÌ ç·¤Øæ ÁæÌæ ãñUÐ ØçÎ ÂýÍ× çSÂ´ý» ×ð´ â´ç¿Ì
çSÍçÌÁ ª¤Áæü 25 J ãUæð Ìæð çmUÌèØ çSÂ´ý» ×ð´ â´ç¿Ì çSÍçÌÁ ª¤Áæü ãUæð»è-
second spring is (1) 25 J
(1) 25 J
(2) 16 J
(2) 16 J
(3) 100 J
(3) 100 J
(4) 20 J
(4) 20 J
135. The temperature of an ideal gas is 68°C. To what 135. °·¤
translational kinetic energy of the molecules be doubled -
¥æÎàæü »ñâ ·¤æ ÌæÂ 68°C ãñUÐ »ñâ ·¤æð ç·¤â ÌæÂ×æÙ Ì·¤ »×ü
·¤ÚÔÚ Ìæç·¤ §Uâ·ð¤ ¥æé¥æð´ ·¤è SÍæÙæÌ´çÚUÌ ¥æñâÌ »çÌÁ ª¤Áæü Îé»éÙè ãUæð
ÁæÌè ãñU-
(1) 547°C
(1) 547°C
(2) 137°C
(2) 137°C
(3) 272°C
(3) 272°C
(4) 820°C
(4) 820°C
temperature should it be heated so that the average
/+1
33
Full Syllabus-IV
136. Which of the following statements is correct (1) In super octet molecule no. of valance electron in central
atom is 10.
(2) Larger the size of cation more will be the tendency of
loosing electron from it.
(3) Smaller the size of cation lesser will be the ionic
character in a compound.
(4) All atomic orbital of valence shell of an atom can enter
into over lapping process.
137. Correct relation is/are (1) Polarising power ∝ φ
(2) φ ∝ Charge on Cation
(3) Polarisation ∝ Polarisability of anion
(4) All of these
138. If lattice energy of sodium chloride is U then lattice energy
of magnesium sulphide is -
136. çÙ×A
×ð´ âð ·¤æñÙâæ ·¤ÍÙ âØ ãñU (1) âéÂÚU ¥CU·¤ ¥æé¥æð´ ·ð¤ ·ð¤çÎýØ ÂÚU×ææé ×ð´ â´ØæðÁè §UÜðÅþUæòÙæð´ ·¤è
â´Øæ 10 ãUæðÌè ãñUÐ
(2) æÙæØÙ ·¤æ ¥æ·¤æÚU çÁÌÙæ ÕÇ¸æ ãUæð»æ §Uâ·ð¤ mUæÚUæ §UÜðÅþUæòÙ Øæ»Ùð
·¤è Âýßëçæ ©UÌÙè ãUè ¥çæ·¤ ãUæð»èÐ
(3) æÙæØÙ ·¤æ ¥æ·¤æÚU çÁÌÙæ ÀUæðÅUæ ãUæð»æ §Uâ ©Uâ Øæñç»·¤ ×ð´ ¥æØçÙ·¤
Üÿææ ©UÌÙð ãUè ØæÎæ ãUæð´»ðÐ
(4) ç·¤âè ÂÚU×ææé ·¤ð â´ØæðÁè ·¤æðàæ ·ð¤ âÖè ÂÚU×æçß·¤ ·¤ÿæ·¤ ¥çÌÃØæÂÙ
×ð´ Öæ» ÜðÌð ãñÚÐ
137. âãUè âÕæ ãñU (1) æýéßæ ÿæ×Ìæ ∝ φ
(2) φ ∝ æÙæØÙ ÂÚU ¥æßðàæ
(3) æýéßæ Âýç·ý¤Øæ ∝ «¤ææØÙ ·¤è æéýßæÌæ
(4) ©UÂÚUæðQ¤ âÖè
138. ØçÎ âæðçÇUØ× ÜæðÚUæ§ÇUU ·¤è ÁæÜ·¤ ª¤Áæü U ãñU, Ìæð ×ñçÙçàæØ× âËÈ¤æ§UÇU
·¤è ÁæÜ·¤ ª¤Áæü ãUæð»è-
(1) 2 U
(1) 2 U
(2) 4 U
(2) 4 U
(3) 6 U
(3) 6 U
(4) None
(4) ·¤æð§üU
139. Minimum number of lone pair on central atom in -
(1) XeO4
(1) XeO4
(2)
ÙãUè´
139. ·¤æñÙâð Øæñç»·¤ ×ð´ ·ð¤ÎýèØ ÂÚU×ææé ÂÚU ØéÙÌ× °·¤æ·¤è §UÜðÅU™æòÙØé×æð´
·¤è â´Øæ ãñU-
SF62
(2) SF62
(3) XeO2F2
(3) XeO2F2
(4) XeF2
(4) XeF2
140. σ-Õ´ææð´ ·¤è ¥çæ·¤Ì× â´Øæ ç·¤â×ð´ ãñ-
140. Maximum number of σ-bond in (1) C2(CN)4
(1) C2(CN)4
(2) H2C = CH CH = CH2
(2) H2C = CH CH = CH2
(3)
(3)
(4) Benzene
(4) Õ´ðÁèÙ
141. Geometry of AX2 type covalent molecule will be (1) Trigonal planner
(2) Tetrahedral
(3) Trigonal bipryamidal
(4) All of these
/+1
Âý·¤æÚU ·ð¤ âãUâ´ØæðÁ·¤ ¥æé ·¤è Øæç×Ìè ãUæð â·¤Ìè ãñU(1) çæ·¤æðæèØ â×ÌÜèØ
(2) ¿ÌécÈ¤Ü·¤èØ
(3) çæ·¤æðæèØ çmUÂçÚUæç×ÇUèØ
(4) ©ÂÚUæðÌ âÖè
141. AX2
34
Full Syllabus-IV
142. Calculate the covalent radius of carbon by using stevenson 142. SÅUèßðâÙ
ÌÍæ S·¤æð×ð·¤ÚU âêæ mUæÚUæ ·¤æÕüÙ ·¤è âãUâ´ØæðÁ·¤ çæØæ ææÌ
·¤èçÁ° -
and schomaker formula -
¥æé SiC ·¤è Õ´æ ÜÕæ§üU 1.40 Å
¥æé Si2 ·¤è Õ´æ ÜÕæ§üU 1.26 Å
C ·¤è çßléÌ «¤æÌæ = 2.5
Si ·¤è çßléÌ «¤æÌæ = 1.8
Bond lenght of SiC molecule 1.40 Å
Bond lenght of Si 2 molecule 1.26 Å
Electronegativity of C = 2.5
Electronegativity of Si = 1.8
(1) almost 0.83 Å
Ü»Ö» 0.83 Å
(2) Ü»Ö» 0.93 Å
(3) Ü»Ö» 0.40 Å
(4) ·¤æð§üU ÙãUè´
143. °·¤ ¥æßÌü ×ð´ ÕæØð´ âð ÎæØð´ ¿ÜÙð ÂÚU ·¤æðàæ ·¤è â´Øæ(1)
(2) almost 0.93 Å
(3) almost 0.40 Å
(4) None
143. In a period when we move from left to right the number of
shell
(1) ÕÉ¸UÌè
(1) increases
(2) decreases
(3) constant
(4) None of these
144. Which of the following complexes formed by Cu2+ ions is
most stable ?
ãñU
(2) æÅUÌè ãñU
(3) çSÍÚU ÚUãUÌè ãñU
144. Cu2+ ¥æØÙæð´ mUæÚUæ ÕÙæØð »Øð çÙÙæ´ç·¤Ì â´·é¤Üæð´ ×ð´ âÕâð ¥çæ·¤
SÍæØè ãñU-
(1) Cu2+ + 4NH3
[Cu(NH3)4]2+, log K = 11.6
(1) Cu2+ + 4NH3
[Cu(NH3)4]2+, log K = 11.6
(2) Cu2+ + 4CN
[Cu(CN)4]2, log K = 27.3
(2) Cu2+ + 4CN
[Cu(CN)4]2, log K = 27.3
(3) Cu 2+ + 2en
(4) Cu2+ + 4H2O
[Cu(en)2]2+, log K = 15.4
(3) Cu2+ + 2en
[Cu(H 2O)4]2+, log K = 8.9
(4) Cu2+ + 4H2O
145. Which of the following species is not expected to be a 145.
[Cu(en)2]2+, log K = 15.4
[Cu(H2O)4]2+, log K = 8.9
çÙÙ ×ð´ âð ·¤æñÙâè SÂèàæèÁ çÜ»ðÇU ÙãUè´ ãñU-
ligand ?
(1) NO
(2) NH4
(1) NO
+
(2) NH4+
(3) NH2CH2CH2NH2
(3) NH2CH2CH2NH2
(4) CO
(4) CO
are not correctly marked against the compound ?
çÙÙ Øæñç»·¤æð´ð ·ð¤ âæ×Ùð ÂýÎçàæüÌ ÂýæÍç×·¤ ß çmUÌèØ·¤ â´ØæðÁ·¤Ìæ°´
ç·¤â×ð´ âé×ðçÜÌ ÙãUè´ ãñU-
(1) [Cr(NH3)6]Cl3, p = 3, s = 6
(1) [Cr(NH3)6]Cl3, p = 3, s = 6
(2) K2[PtCl4], p = 2, s = 4
(2) K2[PtCl4], p = 2, s = 4
(3) [Pt(NH3)2Cl2], p = 2, s = 4
(3) [Pt(NH3)2Cl2], p = 2, s = 4
(4) [Cu(NH 3)4]SO4, p = 4, s = 4
(4) [Cu(NH3)4]SO4, p = 4, s = 4
146. Which of the following primary and secondary valencies 146.
147. Among the following which are ambidentate ligands ?
147.
çÙÙ ×ð´ âð ·¤æñÙâð ©UÖØÎÌé·¤ çÜ»ðÇU ãñU -
(i) SCN
(ii) NO3
(i) SCN
(ii) NO3
(iii) NO2
(iv) C2O42
(iii) NO2
(1) i and iii
(2) i and iv
(1) i ÌÍæ iii
(iv) C2O42
(2) i ÌÍæ iv
(3) ii and iii
(4) ii and iv
(3) ii ÌÍæ iii
(4) ii ÌÍæ iv
/+1
35
Full Syllabus-IV
148. Mark the correct labelling of different terms used in 148.
coordination compounds.
©UÂâãUâ´ØæðÁ·¤ Øæñç»·¤æð ×ð´ ·¤æ× ×ð´ çÜØð »Øð çßçÖóæ ÂÎæð ·¤æð âãUè
É¸U» âð ç¿ãUèÌ ·¤èçÁ° -
[Co(NH3)6 ]Cl3
(iv) (i)
[Co(NH3)6 ]Cl3
(iii) (ii)
(iv) (i)
(1) (i) Central atom, (ii) Ionisation sphere,
(iii) Coordination number, (iv) Ligands
(2) (i) Ligands, (ii) Coordination number,
(iii) Valency, (iv) Ionisation sphere
(3) (i) Ionisation sphere, (ii) Ligands,
(iii) Coordination number, (iv) Central atom
(4) (i) Ligands, (ii) Ionisation sphere,
(iii) Coordination number, (iv) Central atom
∆
⎯→ A + B + O2
149. LiNO3 ⎯ ⎯
(4) Li2O ÌÍæ N2
(4) Li2O and N2
150. ¥âØ
150. Incorrect statement is (1) Anhydrous AlCl3 is covalent
(2) Hydrated AlCl3 is ionic
(3) AlCl3 shown dimerisation
(4) In dimeric form of AlCl3, the covalency of carbon is
only 4
151. Ozonolysis of 2Methyl2butene gives
(1) Acetone and acetaldehyde
(2) Isobutyraldehyde and formaldehyde
(3) Butanone and methanal
(4) Butyraldehyde and formaldehyde
152. Which of the following is most acidic :-
(4) cyclohexanol
/+1
-
(3) Li2O ÌÍæ NO2
(3) Li2O and NO2
(3) m-chloro phenol
∆
⎯→ A + B + O2
149. LiNO3 ⎯ ⎯
(2) Li2O ÌÍæ N2O
(2) Li2O and N2O
(2) benzyl alcohol
â×ßØ â´Øæ, (iv) çÜ»ðÇU
(2) (i) çÜ»ðÇU, (ii) â×ßØ â´Øæ,
(iii) â´ØæðÁ·¤Ìæ, (iv) ¥æØÙÙ ×ÇUÜ
(3) (i) ¥æØÙÙ ×ÇUÜ, (ii) çÜ»ðÇU,
(iii) â×ßØ â´Øæ, (iv) ·ð¤ÎýèØ ÂÚU×ææé
(4) (i) çÜ»ðÇU, (ii) ¥æØÙÙ ×ÇUÜ ,
(iii) â×ßØ â´Øæ, (iv) ·ð¤ÎýèØ ÂÚU×ææé
(iii)
(1) Li2O ÌÍæ LiNO2
(1) Li2O and LiNO2
(1) phenol
(1) (i) ·ð¤ÎýèØ ÂÚU×ææé, (ii) ¥æØÙÙ ×ÇUÜ,
A ÌÍæ B ·ý¤×àæÑ
A and B respectively -
(iii) (ii)
·¤ÍÙ ãñU(1) çÙÁüÜè·ë¤Ì AlCl 3 âãUâ´ØæðÁ·¤ ãñU
(2) ÁÜØæðçÁÌ AlCl3 ¥æØçÙ·¤ ãñU
(3) AlCl3 çmUÜè·¤ÚUæ ÎàææüÌæ ãñU
(4) AlCl3 ·¤è çmUÜè·¤ÚUæ ¥ßSÍæ ×ð´ ·¤æÕüÙ ·¤è ©UÂâãUâ´ØæðÁ·¤Ìæ
·ð¤ßÜ 4 ãUæðÌè ãñU
151. 2esfFky 2C;wVhu ds vkstksuhdj.k }kjk curk gS
(1) ,flVksu vkSj ,lhVsYMhgkbM
(2) vkblks C;wfVjSfYMgkbM vkSj QkWeZ,sfYMgkbM
(3) C;wVsuksu vkSj esFksusy
(4) C;wVkbjsfYMgkbM vkSj QkWesZfYMgkbM
152. fuEu esa ls dkSu vf/kdre vEyh; gS %&
(1) fQukWy
(2) csafty ,Ydksgy
(3) mDyksjks fQukWy
(4) lkbDyks gSDlsukWy
36
Full Syllabus-IV
( i) A
⎯⎯→
+
153. Aceton ⎯
( ii)H 3 O
OH
(1) CH3CH2CH2MgX
(2)
(3)
(4) All
MgX
MgX
NBS
Alco. KOH
⎯ ⎯⎯→ (A) ⎯ ⎯ ⎯ ⎯
⎯→ (B)
(3)
(4) âÖè
MgX
NBS
Alco. KOH
⎯ ⎯⎯
→ (A) ⎯ ⎯⎯⎯
⎯→ (B)
hν /Br
(2)
AgCN
2
4
(1)
(2)
CN
HNO 3
AlCl3
⎯ ⎯⎯
⎯→ (B) B ãUæð»æ ?
⎯ ⎯⎯
→
CH − Cl (A)
H SO
155.
3
2
4
CH !
CH !
(2)
(1)
NO
NO
NO
NO
CH !
NO
NC
(4)
NC
CH !
CH !
(2)
NC
(3)
CN
HNO 3
AlCl3
⎯ ⎯⎯
⎯→ (B), B will be ?
⎯ ⎯⎯
→
CH − Cl (A)
H SO
3
(1)
NC
(4)
NC
(3)
MgX
D ãUæð»æ ?
NC
155.
(2)
2
⎯ ⎯ ⎯⎯
→ (C) ⎯ ⎯ ⎯
⎯→ (D)
D will be ?
(3)
(1) CH3CH2CH2MgX
154.
hν /Br2
AgCN
⎯ ⎯⎯
⎯→ (C) ⎯ ⎯⎯
⎯→ (D)
(1)
.
A Øæ ãñU ?
What is A ?
154.
OH
( i) A
⎯⎯→
+
153. °çâÅUæðÙ ⎯
( ii)H 3 O
.
CH !
NO
2
(4) All
(3)
NO
NO
(4) âÖè
2
156. Electrolytic reduction of nitro benzene in weakly acidic 156. ÎéÕüÜ ¥ÜèØ ×æØ× ×ð´ Ùæ§UÅþUæð Õð´ÁèÙ ·¤æ ¥Â¿ØÙ ·¤ÚUÙð ÂÚU ÎðÌæ ãñU medium gives
(1) Aniline
(1) Aniline
(2) p-hydroxy aniline
(2) p-hydroxy aniline
(3) Phenyl hydroxyl amine
(3) Phenyl hydroxyl amine
(4) Azo benzene
(4) Azo benzene
/+1
37
Full Syllabus-IV
157.Glucose can be tested by following
157. Xyqdksl
(1) Tollen's reagent
(2) Fehling's solution
(3) Both of these
(4) None of these
158. Which of the following is an Antidiabetic drug
dk fuEu ds }kjk ijh{k.k fd;k tk ldrk gS
(1) VkWysu vfHkdeZd
(2) Qsgfyax foy;u
(3) nksuksa ds }kjk
(4) buesa ls dksbZ ugha
158. fuEu esa ls dkSulk e/kqesg jks/kh gS&
(1) Insulin
(2) Penicellin
(1) Insulin
(2) Penicellin
(3) Chloroquin
(4) Asprin
(3) Chloroquin
(4) Asprin
159. Which of the following has highest boiling point:-
159. çÙÙ
×ð´ âð ç·¤â·¤æ ßÍÙæ´·¤ ¥çæ·¤Ì× ãUæðÌæ ãñU-
(1) CH3CH2CH2CHO
(1) CH3CH2CH2CHO
(2) CH3CH2CH2CH2OH
(2) CH3CH2CH2CH2OH
(3) C2H5OC2H5
(3) C2H5OC2H5
(4) CH3CH2CH2CH
(4) CH3CH2CH2CH
160. Arrange the following carbanions in decreasing order of 160. çÙÙçÜç¹Ì
·¤æÕü°ÙæØÙ ·ð¤ SÍæçØß ·¤æ æÅUÌæ ãéU¥æ ·ý¤× ãUæð»æ-
stability :-
(1) P > Q > R > S
(1) P > Q > R > S
(2) S > Q > P > R
(2) S > Q > P > R
(3) S > Q > R > P
(3) S > Q > R > P
(4) Q > S > R > P
(4) Q > S > R > P
161. Which of the following monomerpolymer are not correctly 161. çÙÙçÜç¹Ì
matched -
×ð´ âð ·¤æñÙâæ °·¤Ü·¤-ÕãéUÜ·¤ âãUè âé×ðçÜÌ ÙãUè´ ãñU -
(1) Caprolactam Nylon6
(1) Caprolactam Nylon6
(2) F2C=CF2 PTFE
(2) F2 C=CF2 PTFE
(3) Vinyl chloride PVC
(3) Vinyl chloride PVC
(4) Styrene Natural rubber
(4) Styrene Natural rubber
162. The reaction of HBr with the following compound would 162. çÙÙ Øæñç»·¤ ·¤è HBr âð ç·ý¤Øæ âð ©UÂæÎ
produce -
(1)
(2)
(1)
(2)
(3)
(4)
(3)
(4)
/+1
ÕÙÌæ ãñU-
38
Full Syllabus-IV
163. In a SN2 substitution reaction of the type
163.
R Cl + Br
R Br + Cl
which one of the following has the highest relative rate ?
R Br + Cl
R Cl + Br
çÙÙ ×ð´ âð ç·¤â·¤è ©UæÌ× ¥æÂðçÿæ·¤ ÎÚU ãUæð»è-
(1)
(1)
(2)
(2)
(3)
(3)
(4)
(4)
164. Which of the following compounds undergoes nitration
at fastest rate ?
(1)
164.
çÙÙ Øæñç»·¤æð´ ×ð´ âð ç·¤â·¤æ Ùæ§UÅþUè·¤ÚUæ ÌèßýÌæ âð ãUæðÌæ ãñU-
(1)
(2)
(2)
(3)
(3)
(4)
(4)
165. Which of the following donot give RH with RMgCl (1) NH3
165. çÙÙ
×ð´ âð ·¤æñÙâæ RMgCl ·ð¤ âæÍ RH ÙãUè´ ÎðÌæ ãñU-
(1) NH3
(2) CH3OH
(2) CH3OH
(3) ClNH2
(3) ClNH2
(4) HCOOH
166. The empirical formula of a non-electrolyte is CH2O. A
solution containing 6 g of the compound in 1 litre exerts
the same osmotic pressure as that of 0.05 M glucose solution
at the same temperature. The molecular formula of the
compound is (1) C2H4O2
(2) C3H6O3
(3) C5H10O5
(4) C4H8O4
/+1
§Uâ Âý·¤æÚU ·¤è SN2 ÂýçÌSÍæÂè ¥çÖç·ý¤Øæ ×ð´
(4) HCOOH
166. °·¤
çßléÌ ¥Ù¥ÂæÅU÷Ø ·¤æ ×êÜæÙéÂæÌè âêæ CH2O ãñUÐ °·¤ çßÜØÙ
çÁâ×ð´ ©UÂÚUæðQ¤ Øæñç»·¤ ·¤æ 6 g v ÜèÅUÚU ×ð´ ©UÂçSÍÌ ãñU ·¤æ ÂÚUæâÚUæ
ÎæÕ â×æÙ ÌæÂ ÂÚU 0.05 M Üê·¤æðÁ ·ð¤ ÂÚUæâÚUæ ÎæÕ ·ð¤ â×æÙ ãñU, Ìæð
Øæñç»·¤ ·¤æ âêæ ãUæð»æ-
(1) C2H4O2
(2) C3H6O3
(3) C5H10O5
(4) C4H8O4
39
Full Syllabus-IV
167. At a given temperature, total vapour pressure in Torr of a 167. Îæð
mixture of volatile components A and B is given by
ßæcÂàæèÜ æÅU·¤æð´ A ÌÍæ
çÙ×AæÙéâæÚU çÎØæ »Øæ ãñU-
PTotal = 120 75 XB
B
·¤æ ·é¤Ü ßæcÂÎæÕ °·¤ çÙØÌ ÌæÂ ÂÚU
PTotal = 120 75 XB
hence, vapour pressure of pure A and B respectively (in
A ÌÍæ B
·¤æ àæéhU ¥ßSÍæ ×ð´ ßæcÂÎæÕ ·ý¤×àæÑ (in Torr) ãUæð»æ -
Torr) are
(1) 120, 75
(1) 120, 75
(2) 120, 195
(2) 120, 195
(3) 120, 45
(3) 120, 45
(4) 75, 45
(4) 75, 45
168. If 1 ml of water contains 20 drops. Then number of 168. ÁÜ
molecules in a drop of water is ( d = 1 g/ml) (1) 6.023 × 1023 molecules
(2) 1.376 × 1026 molecules
(3) 1.344 × 1018 molecules
(4) 1.66×1021 molecules
169. A spherical ball of radius 7 cm contains 56% iron by weight.
If density is 1.4 g/cm3, number of mol of Fe present
approximately is -
·ð¤ 1 ml ¥æØÌÙ ×ð´ ÁÜ ·¤è 20 Õê¡Îð´ ãñU ÌÕ °·¤ Õê¡Î ×ð´ ÁÜ ·ð¤
¥æé¥æð´ ·¤è â´Øæ ãUæð»è-( d = 1 g/ml)
(1) 6.023 × 1023 ¥æé
(2) 1.376 × 1026 ¥æé
(3) 1.344 × 1018 ¥æé
(4) 1.66×1021 ¥æé
169. °·¤ »æðÜæ·¤æÚU »ð´Î çÁâ·¤è çæØæ 7 cm ãñU ×ð´ ÖæÚU âð 56% ¥æØÚUÙ ãñUÐ
ØçÎ æÙß 1.4 g/cm3 ãUæð, Ìæð ©UÂçSÍÌ Fe ·ð¤ ×æðÜ ·¤è Ü»Ö»
â´Øæ ãñU -
(1) 10
(1) 10
(2) 15
(2) 15
(3) 20
(3) 20
(4) 25
(4) 25
170. Which substance is serving as a reducing agent in the 170. çÙ×A ¥çÖç·ý¤Øæ ×ð´ ·¤æñÙâæ ÂÎæÍü ¥Â¿æØ·¤ ÂÎæÍü ·¤è ÌÚUãU ·¤æØü ·¤ÚUÌæ
following reaction ?
ãñU-
14H+ + Cr2O 7 − + 3Ni → 2Cr3+ + 7H2O + 3Ni2+
14H+ + Cr2O % − + 3Ni → 2Cr3+ + 7H2O + 3Ni2+
(1) Ni+2
(1) Ni+2
(2) Ni
(2) Ni
(3) H+
(3) H+
(4) Cr2O % −
(4) Cr2O % −
and reduction ?
ãñU-
(1) NaOH (aq) + CO2 → NaHCO3 (aq)
(1) NaOH (aq) + CO2 → NaHCO3 (aq)
(2) 3SiF4 + 4H2O → 2H 2SiF6 + H 4SiO4
(2) 3SiF4 + 4H 2O → 2H2SiF6 + H4SiO4
(3) 3HNO2 → HNO3 + H2O + 2NO
(3) 3HNO2 → HNO3 + H2O + 2NO
(4) CuO + 2HCl → CuCl2 + H2O
(4) CuO + 2HCl → CuCl 2 + H2O
171. Which one of the following reactions involves both oxidation 171. çÙ×A ¥çÖç·ý¤Øæ¥æð´ ×ð´ âð ç·¤â×ð´ ¥æòâè·¤ÚUæ ß ¥Â¿ØÙ ÎæðÙæð´ àææç×Ü
/+1
40
Full Syllabus-IV
172. âé×ðçÜÌ
172. Match the column
Column I
Column II
·¤èçÁ° -
SÌÖ-I
SÌÖ-II
(A) Mechanical property of colloid (p) Dialysis
(A) ·¤æðÜæò§UÇU
·¤æ Øæ´çæ·¤ »éæ
(B) Purification
(q) Peptization
(B) àææðæÙ
(C) Gold number
(r) Brownian movement
(C) Sßæü
(D) Formation of a sol
(s) Protection
(D) âæòÜ ·¤æ çÙ×æüæ
(p) ¥ÂæðãUÙ
(q) ÂðÅUè·¤ÚUæ
â´Øæ
(1) A-r, B-p, C-s, D-q
(1) A-r, B-p, C-s, D-q
(2) A-s, B-r, C-p, D-q
(2) A-s, B-r, C-p, D-q
(3) A-p, B-r, C-s, D-q
(3) A-p, B-r, C-s, D-q
(4) A-q, B-p, C-s, D-r
(4) A-q, B-p, C-s, D-r
(r)
Õýæ©UÙè »çÌ
(s) ÚUÿææ
173. First three nearest neighbour distance for body centered 173. ·¤æØ
cubic lattice are (edge length of unit cell = a) -
·ð¤çÎýÌ æÙèØ ÁæÜ·¤ ·ð¤ çÜ° ÂýÍ× ÌèÙ çÙ·¤ÅUSÍ ÎêçÚUØæ¡ ãUæð»è
(ØçÎ §U·¤æ§üU âðÜ ·ð¤ ç·¤ÙæÚUð ·¤è ÜÕæ§üU = a ãñU) -
(1) = 2 , =, = 3
(1) a 2 , a, a 3
a
a
, a, a 3
(2)
(3)
3
a, a, a 2
2
(3)
3
a, a, a 2
2
(4)
3
a, a, 3a
2
(4)
3
a, a, 3a
2
(2)
2
174. Form the following E° values of half cells,
174. çÙÙ
2
, a, a 3
¥æü ¿æÜ·¤ âñÜæð´ ·ð¤ E° ×æÙæð´ âð
(i) A + e → A; E ° = 0.24 V
(i) A + e → A ; E ° = 0.24 V
(ii) B + e → B 2; E° = +1.25 V
(ii) B + e → B 2; E° = +1.25 V
(iii) C + 2e → C3; E ° = 1.25 V
(iii) C + 2e → C3; E° = 1.25 V
(iv) D + 2e → D2; E° = +0.68 V
(iv) D + 2e → D2; E° = +0.68 V
What combination of two half cells would result in a cell
with the largest potential?
(1) (ii) and (iii)
(2) (ii) and (iv)
(3) (i) and (iii)
(4) (i) and (iv)
175. A factory produces 40 kg. of calcium in two hours by
electrolysis. How much aluminium can be produced by the
same current in two hours-
·¤æñÙ âð Îæð ¥æü âðÜæð´ ·¤æ â´ØæðÁÙ °·¤ âðÜ ÕÙæØð»æ çÁâ·¤æ ç·¤
¥çæ·¤Ì× çßÖß ãUæð»æ?
(1) (ii) ÌÍæ (iii)
(2) (ii) ÌÍæ (iv)
(3) (i) ÌÍæ (iii)
(4) (i) ÌÍæ (iv)
175. °·¤ Èñ¤ÅþUè çßléÌ ¥ÂæÅUÙ mUæÚUæ Îæð æÅðU ×ð´ 40 kg ·ñ¤çËàæØ× ÕÙæÌè
ãñUÐ â×æÙ ææÚUæ mUæÚUæ Îæð æÅðU ×ð´ ç·¤ÌÙæ °ËØêç×çÙØ× ©UÂæçÎÌ ç·¤Øæ
Áæ â·¤Ìæ ãñU(At wt. of Ca = 10, Al = 27)
(At wt. of Ca = 10, Al = 27)
(1) 22 kg.
(2) 18 kg.
(1) 22 kg.
(2) 18 kg.
(3) 9 kg.
(4) 27 kg.
(3) 9 kg.
(4) 27 kg.
/+1
41
Full Syllabus-IV
176. The standard heat of combustion of a hydrocarbon 176. °·¤
ãUæ§UÇþUæð·¤æÕüÙ Øæñç»·¤ ·¤è ×æÙ·¤ ÎãUÙ ª¤c×æ ãñU-
compound is an/a (1) ×æææ×·¤ »éæ
(1) Extensive property
(2) ·¤æâ´Øæ×·¤ »éæ
(2) Colligative property
(3) ×æææ
(3) Intensive property
(4) Constitutive property
177. In a saturated solution of silver chromate in pure water at
25ºC, the concentration of chromate ion is 2×104mol.lit1.
The solubility product of silver chromate is
SßÌ´æ »éæ
(4) ¥ßØßè »éæ
177. àæéhU ÁÜ ×ð́ 25ºC ÂÚU çâËßÚU ·ý¤æð×ðÅU ·ð¤ âÌë´Ì çßÜØÙ ×ð´ ·ý¤æð×ðÅU
¥æØÙ ·¤è âæÎýÌæ 2×104mol.lit 1 ãñUÐ çâËßÚU ·ý¤æð×ðÅU ·¤æ çßÜðØÌæ
»éæÙÈ¤Ü ãñU-
(1) 2 × 108
(1) 2 × 108
(2) 4 × 108
(2) 4 × 108
(3) 3.2 × 1012
(3) 3.2 × 1012
(4) 3.2 × 1011
(4) 3.2 × 1011
178. Buffering action of a mixture of CH3COOH and CH3COONa 178. CH3COOH ÌÍæ CH3COONa ·ð¤
is maximum when the ratio of salt to acid is equal to-
ç×ææ ·¤è ÕÈ¤ÚU ç·ý¤Øæ ¥çæ·¤Ì×
ãUæðÌè ãñU, ÁÕ Üßæ ß ¥Ü ·¤æ ¥ÙéÂæÌ çÙÙ ·ð¤ ÕÚUæÕÚU ãñU-
(1) 1.0
(2) 100.0
(1) 1.0
(2) 100.0
(3) 10.0
(4) 0.1
(3) 10.0
(4) 0.1
179. A box contains CO(g), Cl2(g) and COCl2(g) in equilibrium 179. °·¤ Âææ ×ð´ CO(g), Cl2(g) ÌÍæ COCl2(g), 1000 K ÂÚU âæØ ÂÚU ãñUÐ
CO(g) ·¤æð
at 1000 K. The removal of CO(g) will
(a) decrease the concentration of COCl2
(b) increase the concentration of Cl2
(c) increase the concentration of COCl2
(d) reduce the concentration of CO as well as Cl2
(1) a and b
(2) b and c
(3) c and d
(4) a, b and c
180. For the hypothetical reaction , A2 + B2 ⎯→ 2 AB , the
mechanism is given as below :
A2
A + A (fast reaction)
A + B ⎯→ AB (Ìèßý ¥çÖç·ý¤Øæ)
(c) The overall molecularity is 4
(d) The rate expression is Rate = k [A] [B2]
/+1
¥çÖç·ý¤Øæ)
A + B ⎯→ AB (fast reaction)
(b) The order of the reaction is 3/2
(4) All
A + A (Ìèßý
A + B2 ⎯→ AB + B (æè×è ¥çÖç·ý¤Øæ)
(a) The rate determining step is A + B2 ⎯→ AB + B
(2) b and c
(3) c and d
A2
A + B2 ⎯→ AB + B (slow reaction)
Then correct statements are :
(1) a and b
ãUÅUæÙð ÂÚU (a) COCl2 ·¤è âæÎýÌæ æÅU ÁæØð»è
(b) Cl2 ·¤è âæÎýÌæ ÕÉ¸U ÁæØð»è
(c) COCl2 ·¤è âæÎýÌæ ÕÉ¸U ÁæØð»è
(d) CO ß Cl 2 ÎæðÙæð´ ·¤è âæÎýÌæ æÅU ÁæØð»è
(1) a ÌÍæ b
(2) b ÌÍæ c
(3) c ÌÍæ d
(4) a, b ÌÍæ c
180. ·¤æËÂçÙ·¤ ¥çÖç·ý¤Øæ A2 + B2 ⎯→ 2 AB ·ð¤ çÜ° ¥çÖç·ý¤Øæ
ç·ý¤Øæçßçæ çÙ×A ãñU-
âØ ·¤ÍÙ ãñU(a) ¥çÖç·ý¤Øæ ÎÚU çÙææüÚU·¤ ÂÎ A + B2 ⎯→ AB + B ãñU
(b) ¥çÖç·ý¤Øæ ·¤è ·¤æðçÅU 3/2 ãñU
(c) ¥çÖç·ý¤Øæ ·¤è ·é¤Ü ¥æéâ´ØÌæ 4 ãñ
(d) ÎÚU ÃØ´Á·¤, ÎÚU = k [A] [B2] ãñU
(1) a ÌÍæ b
(2) b ÌÍæ c
(3) c ÌÍæ d
(4) âÖè
42
Important Instructions for Re-AIPMT Exam-2015
AIPMT ·¤è ßðÕâæ§UÅU ÂÚU ÙØð Âýßðàæ Âæ ÁæÚUè ·¤ÚU çÎØð »Øð ãñÚÐ ÂÚUèÿææ ×ð´ àææç×Ü ãUæðÙð ·ð¤ çÜ° ÙØæ Âýßðàæ Âæ ãUè ×æØ ãUæð»æ °ß´ Âýßðàæ Âæ ·ð¤ âæÍ çÎØð »Øð
çÙÎðüàææð´ ·¤æð ØæÙÂêßü·¤ ÂÉ¸U·¤ÚU ©UÙ·¤æ ÂæÜÙ ·¤ÚÔÚÐ
v.
ÂÚUèÿææÍèü ·ð¤ßÜ çÙÙçÜç¹Ì ÎSÌæßðÁ ãUè ÂÚUèÿææ ·ð¤Îý ÂÚU Üð·¤ÚU ¥æØðÁIPMTU mUæÚUæ ÁæÚUè ÙØæ Âýßðàæ ÂæÐ
Âýßðàæ Âæ ÂÚU ÂæâÂæðÅüU ·ð¤ ¥æ·¤æÚU ·¤è È¤æðÅUæð ç¿Â·¤æ·¤ÚU ©Uâð âØæçÂÌ ·¤ÚUßæÙæ ãñUÐ
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Âýßðàæ Âæ ·ð¤ âæÍ ÂýÎæÙ ç·¤Øð »Øð ÂýÂæ ÂÚU ç¿Â·¤æ§üU »§üU °·¤ ÂæðSÅU·¤æÇüU ·ð¤ ¥æ·¤æÚU ·¤è È¤æðÅUæðÐ
w.
ÂÚUèÿææÍèü çÙÙ ßSÌé¥æð´ ×ð´ âð ç·¤âè ·¤æð Öè ÂÚUèÿææ ·ð¤Îý ×ð´ ÙãUè´ Üð·¤ÚU ¥æØð´Ð
SÅðUàæÙÚUè ¥æ§UÅU× Áñâð ×æñçÜ·¤ âæ×»ýè (çÜç¹Ì Øæ ×éçÎýÌ), ·¤æ»Á ·ð¤ ÅéU·¤Ç¸ð, Øæç×ÌèØ/Âð´çâÜ Õæòâ, ÜæçSÅU·¤ ·¤è ÍñÜè, ·ð¤Ü·é¤ÜðÅUÚU, ·¤Ü×,
ÂðÙ, S·ð¤Ü, Üð¹Ù ÕæðÇüU, ÂðÙ Çþæ§Uß, ÚUÕÚU, Üæò» ÌæçÜ·¤æ, §UÜðÅþUæòçÙ·¤ ·¤Ü×, S·ð¤ÙÚU ¥æçÎÐ
â´¿æÚU ©UÂ·¤ÚUæ Áñâð ×æðÕæ§UÜ È¤æðÙ, ËØêÅéUÍ, §UØÚUÈ¤æðÙ, ×æ§U·ý¤æðÈ¤æðÙ, ÂðÁÚU, SßæSØ Õñ´ÇU ¥æçÎÐ
¥Ø ßSÌé Áñâð ÕÅéU¥æ, Ââü, æêÂ ·ð¤ ¿à×ð, ãñÚÇUÕñ», ãðUØÚU çÂÙ, ãðØÚU Õñ´ÇU, ÌæÕèÁ, ÕðËÅU, ÅUæðÂè, S·¤æÈü¤ ¥æçÎÐ
¹æl ßSÌé°´ ¹éÜè Øæ çÇUÕæ Õ´Î, ÂæÙè ·¤è ÕæðÌÜÐ
¥æÖêáæ Áñâð ¥´»êÆUè, ·´¤»Ù, Ûæé×·ð¤, Ùæ·¤ ·¤è Üæð´», ¿ñÙ, ãUæÚU, ÜÅU·¤Ù, Âð´ÇðUÅU, ÕñÁ, ÁÇUæ©U çÂÙ ¥æçÎÐ
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Áæ â·¤Ìè ãUæðÐ
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âÜßæÚU/ÂÌÜêÙÐ
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ÂÚUèÿææÍèü ·¤æð ¥æß´çÅUÌ ÂÚUèÿææ ·ð¤Îý ÂÚU (ÂýæÌÑ |Ñx® ÕÁð âð ~Ñx® ÕÁð Ì·¤) ÂãéÚ¿Ùæ ãñU çÁââð ©Uâ·¤è ¥çÙßæØü ÌÜæàæè Üè Áæ â·ð¤Ð
z.
ÂýæÌÑ ~Ñx® ÕÁð ·ð¤ ÕæÎ ¥æÙð ßæÜð ÂÚUèÿææÍèü ·¤æð ÂÚUèÿææ ·ð¤Îý ×ð´ Âýßðàæ ÙãUè´ çÎØæ ÁæØð»æÐ
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ª¤ÂÚU çÎØð »Øð çÙÎðüàææð´ ·¤æ ÂæÜÙ ÙãUè´ ·¤ÚUÙð ßæÜð ÂÚUèÿææÍèü ·¤æð ÂÚUèÿææ ·ð¤Îý ×ð´ Âýßðàæ ÙãUè´ çÎØæ ÁæØð»æÐ
1. The candidates will bring only the following documents at the examination centre (No photograph will he clicked at the centre) :
a) Admit Card with passport size photograph affixed on it
b) one Postcard Size Photograph affixed on the proforma provided with admit card and
c) one passport size photograph to be affixed on attendance sheet.
2. The candidates will not bring any of the following items at the centre:
a) Stationery items like textual material (printed or written), hits of papers, Geometry/Pencil Box, Plastic Pouch, Calculator, Pen, Scale,
Writing Pad, Pen Drives, Eraser, Calculator, Log Table, Electronic Pen/Scanner etc;
b) Communication devices like Mobile Phone, bluetooth, Earphones, Microphone, Pager, Health Band etc;
c) Other items like Wallet, Goggles, Handbags, Hair Pin, Hair Band, Charm/Tabeez, Belts, Cap,. scarf etc;
d) Ornament like Ring, Bracelet, Earrings, Nose Pin, Chain/Necklace, Pendants, badge, brooch etc;
e) Watch/Wrist Watch, Camera etc;
f) Metallic items and any eatable item (opened or packed), water bottle etc,
g) Any other item which could be used for unfair means and for hiding communication devices like Mobile, Camera, Bluetooth device etc.
3. The candidates will observe the following dress code while coming for appearing in AIPMT Examination:.
a) Wear light clothes with half sleeves Shirt/T-Shirt/Kurta not having big buttons, brooch or any badge, flower and Trouser/Salwar etc
b) Wear open slippers and not the shoes,
4. The candidates will cooperate with the staff at examination centre in frisking.
5. The candidates will report at allotted examination centre well in advance (07.30 am to 09.30 am) to make him/herself available for compul
sory physical frisking.
6. No candidate who reports after 0930 AM shall be allowed to enter in the examination centre.
The candidates found disobeying any of the above instructions will not be allowed to enter in the examination centre and appear in the
examination.
Space for rough work...